The equation for a straight line (deterministic model) is y=β0+β1x. If the line passes through the point (−5,5), then x=−5, y=5 must satisfy the equation; that is, 5=β0+β1(−5). Similarly, if the line passes through the point (2,11), then x=2, y=11 must satisfy the equation; that is, 11=β0+β1(2). Use these two equations to solve for β0 and β1; then find the equation of the line that passes through the points (−5,5) and (2,11). Find β0 and β1. β1=enter your response here β0=enter your response here (Simplify your answers. Type integers or simplified fractions.)

The equation for a straight line (deterministic model) is y=β0+β1x. If the line passes through the point (−5,5), then x=−5, y=5 must satisfy the equation; that is, 5=β0+β1(−5). Similarly, if the line passes through the point (2,11), then x=2, y=11 must satisfy the equation; that is, 11=β0+β1(2). Use these two equations to solve for β0 and β1; then find the equation of the line that passes through the points (−5,5) and (2,11). Find β0 and β1. β1=enter your response here β0=enter your response here (Simplify your answers. Type integers or simplified fractions.)

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter2: Systems Of Linear Equations

Section2.4: Applications

Problem 16EQ

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Question

The equation for a straight line (deterministic model) is

y=β0+β1x.

If the line passes through the point

(−5,5),

then

x=−5,

y=5

must satisfy the equation; that is,

5=β0+β1(−5).

Similarly, if the line passes through the point

(2,11),

then

x=2,

y=11

must satisfy the equation; that is,

11=β0+β1(2).

Use these two equations to solve for

β0

and

β1;

then find the equation of the line that passes through the points

(−5,5)

and

(2,11).

Find

β0

and

β1.

β1=enter your response here

β0=enter your response here

(Simplify your answers. Type integers or simplified fractions.)

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