The equation for a straight line​ (deterministic model) is y=β0+β1x. If the line passes through the point (−10,10)​, then x = −10​, y = 10 must satisfy the​ equation; that​ is, 10=β0+β1(−10). ​Similarly, if the line passes through the point (3,12)​, then x = 3​, y = 12 must satisfy the​ equation; that is, 12=β0+β1(3). Use these two equations to solve for β0 and β1​; then find the equation of the line that passes through the points (−10,10) and (3,12).   A. Find β0 and β1. β1 = β0 =

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 16EQ
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The equation for a straight line​ (deterministic model) is y=β0+β1x.

If the line passes through the point (−10,10)​, then x = −10​, y = 10 must satisfy the​ equation; that​ is, 10=β0+β1(−10).

​Similarly, if the line passes through the point (3,12)​, then x = 3​, y = 12 must satisfy the​ equation; that is, 12=β0+β1(3).

Use these two equations to solve for β0 and β1​; then find the equation of the line that passes through the points (−10,10) and (3,12).

 

A. Find β0 and β1.

β1 =

β0 =

​(Simplify your answers. Type integers or simplified​ fractions.)

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