Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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The enthalpy of vaporization of Substance X is 23.0
Round your answer to 2 significant digits.
0
atm
x10
×
kJ
and its normal boiling point is 10. °C. Calculate the vapor pressure of X at - 18. °C.
mol
Ś
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Transcribed Image Text:The enthalpy of vaporization of Substance X is 23.0 Round your answer to 2 significant digits. 0 atm x10 × kJ and its normal boiling point is 10. °C. Calculate the vapor pressure of X at - 18. °C. mol Ś
Expert Solution
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Step 1: Given information:

The enthalpy of vaporization, increment H subscript v a p end subscript of substance X is given as 23.0 space k J divided by m o l.

The relationship between kJ and J is given by an expression as follows:

1 space k J space equals space 1000 space J

Converting increment H subscript v a p end subscript in J/mol.

increment H subscript v a p end subscript space left parenthesis i n space J divided by m o l right parenthesis space equals space fraction numerator 1000 space J over denominator 1 space k J end fraction space cross times space 23.0 space k J divided by m o l
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 23.0 space cross times space 10 cubed space J divided by m o l

The normal boiling point of the substance X is given as 10 to the power of space o end exponent C.

The temperature at which the vapor pressure of a liquid becomes equal to the atmospheric pressure is called the normal boiling point of that liquid.

We have to determine the vapor pressure of the substance X at negative 18 to the power of space o end exponent C.

The relationship between the temperature in degrees Celsius and the temperature in Kelvin is given by an expression as follows:

T space left parenthesis K right parenthesis space equals space t to the power of space o end exponent C space plus space 273.15

Converting 10 to the power of space o end exponent C in Kelvin.

10 to the power of space o end exponent C space left parenthesis i n space K e l v i n right parenthesis space equals space 10 to the power of space o end exponent C space plus space 273.15
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 283.15 space K

Converting negative 18 to the power of space o end exponent C in Kelvin.

negative 18 to the power of space o end exponent C space left parenthesis i n space K e l v i n right parenthesis space equals space minus 18 to the power of space o end exponent C space plus space 273.15
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 255.15 space K space space space space space space space space space space space

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