University Physics Volume 2
18th Edition
ISBN: 9781938168161
Author: OpenStax
Publisher: OpenStax
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- Check Your Understanding What happens to the ground state energy of an electron if the dimensions of the solid increase?arrow_forwardIn the simple Bohr model of the ground state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 5.281011m , and the speed of the electron is 2.18106m/s . The mass of an electron is 9.111031kg . What is the force on the electron?arrow_forwardCheck Your Understanding The vibrational frequency of the hydrogen iodide HI diatomic molecule is 6.691013Hz. (a) What is the force constant of the molecular bond between the hydrogen and the Iodine atoms? (b) What is the energy of the emitted photon when this molecule makes a transition between adjacent vibration energy levels?arrow_forward
- What is the critical magnetic field for lead at T = 2.8 K?arrow_forwardCheck Your Understanding If a=3+4i , what is the product a* a?arrow_forwardThe force on an electron is “negative the gradient of the potential energy function.” Use this knowledge and Equation 8.1 to show that the force on the electron in a hydrogen atom is given by Coulomb’s force law. Ur=ke2r(8.1)arrow_forward
- Measurements of a superconductor's critical magnetic field (in T) at various temperatures (in K) are given below. Use a line of best fit to determine Bc(0). Assume Tc = 9.3 K.arrow_forwardA section of superconducting wire carries a current of 100 A and requires 1.00 L of liquid nitrogen per hour to keep it below its critical temperature. For it to be economically advantageous to use a superconducting wire, the cost at cooling the wire must be less than the cost of energy lost to heat in the wire. Assume that the cost of liquid nitrogen is $0.30 per liter, and that electric energy costs What is the resistance of a normal wire that costs as much in wasted electric energy as the cost of liquid nitrogen for the superconductor?arrow_forwardFor an electron in a three-dimensional metal, show that the average energy is given by E=1N0EFEg(E)dE=35EF , Where N is the total number electrons in the metal.arrow_forward
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