The electric field 2.5 cm from an unknown charge has a strength of 428 N/C and points toward the charge. (a) What then is the electric potential at that distance, assuming there are no other point charges in the region? Vp = 428 V (b) The electric field strength at a different point near another charge is 315 N/C. How far is this point from the charge if the electric potential there is -33 V? d = cm
The electric field and electric potential for a point charge can be calculated using Coulomb's law and the definition of electric potential.
Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:
F = k * q1 * q2 / r^2
where F is the electrostatic force, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is Coulomb's constant, which has a value of 8.99 × 10^9 N·m^2/C^2.
The electric field at a point in space due to a point charge q is given by:
E = k * q / r^2
where ε0 is the permittivity of free space and r is the distance between the point charge and the point in space where the electric field is being calculated. And E is the electric field at that point.
The electric potential at a point in space due to a point charge q is given by:
V = k * q / r
where V is the electric potential at the point in space, and r is the distance between the point charge and the point in space where the electric potential is being calculated.
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