College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron passes through an area of changing potential as shown below. At point A, the electron has a speed of 7.2 × 106 m/s. What is the approximate speed of the electron at point B? A +10 V 7 +20 V B +30 Varrow_forwardA parallel plate capacitor in air is constructed with two 13 cm x 13 cm square conductors separated by 3 mm. a) Determine the value of the capacitance of this parallel plate capacitor. b) This capacitor is placed across a 12 V battery and allowed to fully charge. What is the value of this charge? To continue, please enter your answer in b) in units of nC. Round your answer to 1 decimal place.arrow_forwardс A slab of copper of thickness b is thrust into a parallel-plate capacitor of plate area A and plate separation d, as shown in the figure above; the slab is exactly halfway between the plates. NOTE: Express your answers in terms of the given variables using eo and q when necessary. (a) What is the capacitance after the slab is introduced? = W b (b) If a charge q is maintained on the plates, what is the ratio of the stored energy before to that after the slab is inserted? d U₁ Uf (c) How much work is done on the slab as it is inserted? = = (d) Is the slab sucked in or must it be pushed in? [Choose one ▾arrow_forward
- Part A The voltage across a 4 μF capacitor increases by 48 V. If the final charge on the capacitor is 507 μC, determine the initial charge. Q₁ = Part B Two parallel plates each have a charge magnitude of 601 nC. Between the plates is a dielectric with K = 86. Additionally, the E-field between the plates is 7.81x105 V/m. Determine the area of each plate. A= Part C A capacitor with no dielectric has an E-field of 88 kV/mm between the plates. The area of each plate is 46.3 cm² and the voltage across the capacitor is 1.5 V. Determine the capacitance. C=arrow_forwardTwo 2.10 cm x 2.10 cm plates that form a parallel- plate capacitor are charged to ±0.708 nC. ▾ Part A What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm? Express your answer with the appropriate units. E= Value Submit Request Answer Part B ? Units What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ? Express your answer with the appropriate units. HÅ V = Value Units Submit Request Answer Part C ? What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. με E = Value Units Submit Request Answer Part D ? What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. ΜΑ ? V = Value Units Submit Request Answer Provide Feedbackarrow_forwarda. Review the method of calculating the electrostatic potential for a conducting sphere. Now since the whole conductor is an equipotential surface, lind the ratio of charge on sphere I to the charge on sphere 2: Q1/Q2. b. Find the ratio of surface charge density on sphere 1 to sphere 2: 01/02. c. Find the ratio of electric field strength on sphere 1 to sphere 2: E1/E2.arrow_forward
- Select the correct expression for the work required to bring the charge q from infinity to a given point in an external potential V. Select one: = qV ? b. W = q²V a. W = O c. W = qVarrow_forwardThe figure(Figure 1) is a graph of E The potential at x=2m is -200 V Part A You may want to review (Pages 715 - 716) What direction is the x-component of the electric field pointing between x=2m and x=3m in the graph? Express your answer to two significant figures and include the appropriate units. E, is pointing rightward (+x-direction) O Not enough information O E, is pointing down (minus y-direction) O E, is pointing up (+y-direction) O E is pointing leftward ( minus x-direction) Figure 1 of 1 Submit Request Answer E, (V/m) Provide Feedback 200 100 x (m) 3. Pearsonarrow_forwardTwo 2.50 cm x 2.50 cm square aluminum electrodes are spaced 0.530 mm apart. The electrodes are connected to a 140 V battery. Part A What is the capacitance? Give your answer in picofarads. (pico = 10-12) ? C = 1.044 pF Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the charge on each electrode? Give your answer in nanocoulombs. Ηνα ΑΣφ x•10" Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remainingarrow_forward
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