The drawing shows two cars traveling in different directions with different speeds. Their velocities are: VAG = velocity of car A relative to the Ground = 27.3 m/s, due east VBG = velocity of car B relative to the Ground = 21.0 m/s, due north The driver of car B looks out the window and sees car A. What is the velocity (magnitude and direction) of car A as observed by the driver of car B? In other words, what is the velocity VAB of car A relative to car B? North Car A VAG VBG Car B East

The vector form of velocities of Car A and Car B is,

${\overrightarrow{V}}_{AG}=(27.3 m/s)\hat{i}$

${\overrightarrow{V}}_{BG}=(21 m/s)\hat{j}$

The velocity of car A as observed by the car B is,

$$\begin{gathered} {\overrightarrow{V}}_{AB}={\overrightarrow{V}}_{AG}-{\overrightarrow{V}}_{BG} \\ =(27.3 m/s)\hat{i}-(21 m/s)\hat{j} \end{gathered}$$