
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question

Transcribed Image Text:'SM
Moon
FSM
Sun
FEM
'EM
Earth

Transcribed Image Text:The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force F SM that the sun exerts on the
moon is perpendicular to the force F EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 x 1030 kg, mass of
earth = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and rEM = 3.85 ×
10° m. Determine the magnitude of the net gravitational force on the moon.
Expert Solution

arrow_forward
Step 1
Given that:
Mass of sun, Ms = 1.99X 1030 kg
Mass of earth,Me = 5.98 X 1024 Kg
Mass of moon, Mm= 7.35X 1022 kg
Radius between sun to moon, rsm = 1.5 X 1011 m
radius between Earth to moon, rem= 3.85 X 108 m
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Sphere A with mass 70 kg is located at the origin of an xy coordinate system; sphere B with mass 73 kg is located at coordinates ( 0.23 m, 0); sphere C with mass 0.55 kg is located at coordinates ( 0.15 m, 0.14 m). In unit-vector notation, what is the gravitational force on C due to A and B?arrow_forwardChapter 13, Problem 011 In the figure, two spheres of mass m = 9.24 kg. and a third sphere of mass M form an equilateral triangle, and a fourth sphere of mass mą is at the center of the triangle. The net gravitational force on that central sphere from the three other spheres is zero. (a) What is the value of mass M? (b) If we double the value of m4, what then is the magnitude of the net gravitational force on the central sphere? M (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: 0 of 10 used SUBMIT ANSWER SAVE FOR LATERarrow_forwardA planet of mass 7.00×1024 kg is at location (-3.75×10¹¹, 6.25×10¹¹, 0) m. A star of mass 8.00×1030 kg is at location (5.00×10¹¹, -4.25×10¹¹, 0) m. What is the force exerted on the planet by the star? (It will probably be helpful to draw a diagram, including the relevant vectors.) on planet =arrow_forward
- Look at the picturearrow_forwardThe mass of a planet is one third that of the earth and the diameter of the planet is six times that of the earth. What is the acceleration due to gravity on the surface of the planet? Given g on earth is 9.8 ms-2.arrow_forwardwhat are the magnitude and direction of the gravitational force exerted on Moe by 11.lf Moe exerts a gravitational force of 3.65 x 10-8 N on Larry, who is standing east of him, 10.If an object on the earth experiences a gravitational force of 25 N toward the center of the earth, what are the magnitude and direction of the force the object exerts on the earth? Larry? If each man has a mass of 70.0 kg, how far apart are they standing? If Curly were to bump into Moe, knocking him halfway to Larry, how would the new gravitational force between Moe and Larry compare to the original? a. ¼ as great b. ½ as great c. the same d. twice as great e. four times as greatarrow_forward
- Compare the magnitude of the gravitational field at the surface of the earth due to the moon with that due to the sun. (Hint: The mass of the sun is 1.99 x 10^30 kg, the mass of the moon is 7.36 x 10^22 kg, and the distance from the surface of the earth to the moon is 3.78 10^8 m.)arrow_forwardIn the year 25 000 the Earth is 1.42x101 m away from the sun and in a circular orbit, but a year remains 365 days long. Part A Calculate the mass of the sun in the year 25 000. ΑΣΦ ? msun = kgarrow_forwardQuestion 4 Please !!!arrow_forward
- During a solar eclipse, the Moon is positioned directly between Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99×10^30 kg, 5.98×10^24 kg, and 7.36×10^22 kg, respectively. The Moon's mean distance from Earth is 3.84×10^8 m, and Earth's mean distance from the Sun is 1.50×10^11 m. The gravitational constant is G=6.67×10^−11 N·m2/kg^2. Find the magnitude F of the net gravitational force acting on the Moon during the solar eclipse due to both Earth and the Sun.arrow_forwardExoplanet Taphao Keow is a Jupiter-sized planet orbiting another star. It has a mass of approximately 1×10+27[kg]. Its actual radius is not currently known, but we do know that the radius of Jupiter is 7×107[m]. Question: If Taphao Keow had a radius that was the same radius as Jupiter, what would it's local surface gravitational acceleration be? O 266 [m/s2] 124 [m/s²] 70 [m/s²] O 24 [m/s²] O 14 [m/s²] It would have a gravitational acceleration far larger than any of the other answers (many orders of magnitude larger) It would have a gravitational acceleration far smaller than any of the other answers (many orders of magnitude larger)arrow_forwardA new planet named Vulcan has been discovered. Vulcan is a rather large planet with a radius twice that of Earth and a mass three times that of Earth. An astronaut has a mass of 60.0 kg and weighs about 132 lbs. on Earth. If the astronaut is on the planet Vulcan, what is her weight? The following numerical values may be helpful in this question. G = 6.67 ∙10-11 N∙m2/ kg2 Earth’s mass = 5.98 · 1024 kilograms g = 9.80 m/sec2 1 kilometer = 1000 metersarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON

College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning

University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley

College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON