The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force F SM that the sun exerts on the moon is perpendicular to the force F EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 × 1030 kg, mass of earth = 5.98 × 1024 kg, mass of moon = 7.35 × 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and rEM = 3.85 x 10° m. Determine the magnitude of the net gravitational force on the moon.

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11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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'SM
Moon
FSM
Sun
FEM
'EM
Earth
Transcribed Image Text:'SM Moon FSM Sun FEM 'EM Earth
The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force F SM that the sun exerts on the
moon is perpendicular to the force F EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 x 1030 kg, mass of
earth = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and rEM = 3.85 ×
10° m. Determine the magnitude of the net gravitational force on the moon.
Transcribed Image Text:The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force F SM that the sun exerts on the moon is perpendicular to the force F EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 x 1030 kg, mass of earth = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsM = 1.50 × 1011 m and rEM = 3.85 × 10° m. Determine the magnitude of the net gravitational force on the moon.
Expert Solution
Step 1

Given that:

Mass of sun, Ms = 1.99X 1030 kg

Mass of earth,Me = 5.98 X 1024 Kg

Mass of moon, Mm= 7.35X 1022 kg

Radius between sun to moon, rsm = 1.5 X 1011 m

radius between Earth to moon, rem= 3.85 X 108 m

 

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