The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 272 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 41 54 44 55 39 51 328 528 418 580 296 503 What is the regression equation? =+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 40 inches? The best predicted weight for a bear with a chest size of 40 inches is pounds. (Round to one decimal place as needed.) le the result cloen to the actual uninht of 272 nounde? Copyright © 2022 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy Permissions Contact Us a Next 88°F 2:43 7/31/

Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.9 cm. How does the result compare to the actual circumference of 6.0 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball 5 Diameter 7.4 23.6 4.3 21.7 7.1 3.9 21.5 Circumference 23.2 74.1 13.5 68.2 22.3 12.3 67.5

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 41 inches. Is the result close to the actual weight of 153 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 40 53 38 43 44 58 D 227 360 153 206 234 414 What is the regression equation? y=+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 41 inches? The best predicted weight for a bear with a chest size of 41 inches is (Round to one decimal place as needed.) Is the result close to the actual weight of 153 pounds? O A. This result is exactly the same as the actual weight of the bear. O B. This result is close to the actual weight of the bear. O C. This result is very close to the actual weight of the bear. O D. This…

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 392 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) E Click the icon to view the critical values of the Pearson correlation coefficient r. 41 54 44 55 39 51 328 528 418 580 296 503 ..... What is the regression equation? y =+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 40 inches? The best predicted weight for a bear with a chest size of 40 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 392 pounds? O A. This result is close to the actual weight of the bear. O B. This result is exactly the same as the actual weight of the bear. O C. This result is very close to the actual weight of the…

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Find the regression​ equation, letting overhead width be the predictor​ (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2.5 cm. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case? Use a significance level of 0.05.   Overhead Width​ (cm) 7.6 7.4 9.8 8.8 9.3 7.3   Weight​ (kg) 142 163 256 188 231 156       The regression equation is y= + x. ​(Round to one decimal place as​ needed.)   The best predicted weight for an overhead width of 2.5 cm is kg? ​(Round to one decimal place as​ needed.)   Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?     A. The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.   B. The prediction cannot be correct because a negative weight does not make sense and because there is…

The paired data below consists of heights and weights of 6 randomly selected adults. Find the linear correlation coefficient, the linear regression line, and predict the weight of a randomly selected person who is 1.69 meters tall. X Height (meters) 1.61 1.72 1.78 1.80 1.67 1.88 Y Weight (kg) 54 62 70 84 61 92

Prev The table below gives the age and bone density for five randomly selected women. Using this data, consider the equation of the regression line, y = bo + b₁x, for predicting a woman's bone density based on her age. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, In practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant. Age Bone Density 61 62 68 69 40 357 350 343 340 315 Step 1 of 6: Find the estimated slope. Round your answer to three decimal places. Table Copy Data Next

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 48 inches. Is the result close to the actual weight of 308 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 58 49 58 43 46 57 355 266 332 177 246 348 What is the regression equation? y = + x (Round to one decimal place as needed.) %3D What is the best predicted weight of a bear with a chest size of 48 inches? The best predicted weight for a bear with a chest size of 48 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 308 pounds? A. This result is not very close to the actual weight of the bear. B. This result is close to the actual weight of the bear. C. This result is exactly the same as the actual weight of the bear.…