76 ll 6Q3.pngThe data from standard and modified proctor test on a soil sample (density of solids: 2680 kg/m3 ) areprovided below:Standard proctor testModified proctor testDry density (kg/m’)1873Dry density (kg/m®)Water content (%)Water content (%)16919.39.3171511.8191012,8175514.3180315.5174717.6169918.7168520.8164121.1161923a) Plot the compaction curves (both standard and modified in one graph).b) Establish the maximum dry density and optimum water content for each test.

Compaction is the procedure of reducing the air void present in the soil that is dense the soil.…

The data from standard and modified proctor test on a soil sample (density of solids: 2680 kg/m3 ) are provided below: Standard proctor test Modified proctor test Dry density (kg/m Water content (%) Dry density (kg/m') 9.3 11.8 14.3 1691 1715 1755 1747 1873 1910 1803 1699 Water content (%) 9.3 12.8 15.5 18.7 21.1 17.6 1685 1619 20.8 23 1641 a) Plot the compaction curves (both standard and modified in one graph). b) Establish the maximum dry density and optimum water content for each test.

The data from standard and modified proctor test on a soil sample (density of solids: 2680 kg/m3 ) are provided below: Standard proctor test Modified proctor test Dry density (kg/m Water content (%) Dry density (kg/m') 9.3 11.8 14.3 1691 1715 1755 1747 1873 1910 1803 1699 Water content (%) 9.3 12.8 15.5 18.7 21.1 17.6 1685 1619 20.8 23 1641 a) Plot the compaction curves (both standard and modified in one graph). b) Establish the maximum dry density and optimum water content for each test.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In the dry sieve analysis of soil the sieves 10 are placed as sequential order one below the other as: eutme 75 mm, 63 mm,37.5 mm,28 mm, 20 mm, 1dy af 14 mm, 10 mm, 6.3 mm, 4.75mm, 2.36mm, 1.18mm, 600µ, 300p,150µ,75µ, pan nere Select one: True False
From your Atterberg limits tests on the -40 portion of these samples, you have obtained the following data Percentage finer by weight 100% 80% 60% 40% 20% Soil Sample Identification 0% 0.001 H I J L FINES 0.010 H Liquid Limit 60 46 37 Plastic Limit 26 nonplastic #200 34 18 Fine SAND Medium Course 0.100 Particle size (mm) 1.000 #4 danastants GRAVEL Fine 10.000 Coarse 3" 100.000
Classify Soil C (group classification and group index) using AASHTO method. SOIL SAMPLE SIEVE NO. DIA. (mm) A В # 4 4.76 90 100 100 # 8 2.38 88 90 100 # 10 2 86 77 98 # 20 0.84 84 59 92 # 40 0.42 82 56 84 # 60 0.25 80 54 79 #100 0.15 78 51 75 #200 0.075 76 48 72 Characteristics of # 40 fraction LL 38 28 50 PL 30 45
43.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 100 6 2.380 98 10 2.000 91 20 0.840 85 40 0.420 84 60 0.250 79 100 0.149 61 200 0.074 55 LL 60 PL 40 ML None of the above. CL CH MH
PROBLEM 7: The laboratory results of a soil test are as follows: Sieve No. # 4 #10 #40 #200 LL PL Percent passing 100 93.20 81 55 45 17 Find the group index according to AASHTO classification system. Hint: GI = (F-35)[0.20 + 0.005(LL – 40)] + 0.01(F – 15)(PI – 10)
EAM MAN TESİ MSKŪ-LMS Hydrometer and sieve analysis were conducted on a soil sample. amadı Find D10, D60, uniformity coefficient (Cu), coefficient of curvature (CC) considering the chart given below. erinden Hint: Cu=D60/D1o and CC=(D30)2 / (D10XD60) miş 100 90 80 70 60 50 40 30 20 10 SILT SAND GRAVEL 100 0,001 CLAY 0,1 10 0,01 DANE ÇAPI / PARTICLE SIZE (mm) D20: (in mm) Seς Seç. Cu 14.28 0.1 Deo: (in mm) 5.14 0.007 CC Consolidation test results are provided below, (Hint: C, or Ce = Ae/log(of/ai') ): nmadi zerinden nmiş AR 21 lenov GEÇEN DANE YÜZZDESİ / PERCENT FINER THAN D
42.) The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 96 6 2.380 91 10 2.000 89 20 0.840 85 40 0.420 81 60 0.250 78 100 0.149 67 200 0.074 64 LL 40 PL 30 MH CH ML None of the above CL
4. The table below shows the laboratory results of the sample. Determine the soil classification using Unified Soil Classification System (USC). Sieve No. Opening (mm) Percent Passing 4 4.760 90 8 2.380 64 10 2.000 58 20 0.840 35 40 0.420 22 60 0.250 15 100 0.149 0.074 10 200 4 D10 = 0.15mm, D30 = 0.65mm, D60 = 2.20mm %3D
4. From the given data, shows a sieve analysis of soil samples A, B and C. SOIL SAMPLE Sieve No. Diam (mm) A В C PERCENT PASSING 4 4.460 90 100 100 8 2.380 64 90 100 10 2.00 54 77 98 20 0.840 34 59 92 40 0.420 22 51 84 60 0.250 17 42 79 100 0.149 9. 35 70 200 0.074 4 33 63 Characteristics of -40 Fraction LL 46 47 PL 29 24 a. Classify the soil sample A using USCS method (Group Symbol only), D.=2.3, D = 0.17, b. Classify the soil sample B using AASHTO method c. Classify the soil sample C using the AASHTO method D = 0.70 30
76 .ll Q3.png The data from standard and modified proctor test on a soil sample (density of solids: 2680 kg/m3 ) are provided below: Standard proctor test Modified proctor test Dry density (kg/m) 1691 Dry density (kg/m') 1873 Water content (%) Water content (%) 9.3 9.3 1715 11,8 1910 12.8 1755 14.3 1803 15.5 1747 17.6 1699 18.7 1685 20.8 1641 21.1 1619 23 a) Plot the compaction curves (both standard and modified in one graph). b) Establish the maximum dry density and optimum water content for each test.
dys.mu MSKÜ-LMS 016 ŞB: 1 ÖRGÜN Soil Mechanics Mühendislik Fakültesi Mac Atterberg limits of a soil sample are given: LL:55% and PL:25%. Give the name of the soil typle considering the chart given below? Remember PI=LL-PL 60 U-line PI - 0.9 (LL -8) 50 Z 40 CH or OH A-line PI0.73 (LL - 20) 30 CL OH 20 or OL MH CL- ML 10 ML& OL 10 20 30 40 50 60 70 80 90 100 Liquid limit (%) O a. CL or OL O b. CH OR OH O c. OH or ML O d. GL or ML O e. M ail E AR .ill lenovo Plasticity index (%)
A sample soil is obtained and sieve analysis is performed to determined its particle distribution. Sieve Opening Mass Retained % Finer # 6 3.35 146 # 8 2.36 88 #16 1.18 125 # 40 0.425 56 #50 0.3 42 #140 0.106 127 # 200 0.075 126 Pan 29 Determine: 1. Effective Size (in mm and in 4 decimal places) 2. Uniformity Coefficient (in 2 decimal places) 3. Coefficient of Curvature (in 2 decimal places) 4. Sorting Coefficient (in 2 decimal places)