The contingency table to the right shows counts of the types of gasoline bought during the week and during weekends. (a) Find the value of chi-squared and Cramer's V for this table. (b) Interpret these values. What do these tell you about the association in the table? (a) x² = (Round to two decimal places as needed.) C Premium Plus Regular Total Weekday Weekend 34 39 46 274 511 35 591 348 Total 73 320 546 939
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Please explain how to calculate chi squared and cramer's V showing steps. Thank you so much.
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- A researcher is looking at a new marketing campaign for a product. After 200 people watched the marketing campaign about 60 percent liked the product. Prior to the marketing campaign the product was liked by about 50 percent of people. What are the chi-square test degrees of freedom for this research description?A researcher is looking at a new marketing campaign for a product. After 200 people watched the marketing campaign about 60 percent liked the product. Prior to the marketing campaign the product was liked by about 50 percent of people. What is the chi-square cutoff for an alpha of 0.05 for this research project?A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 10 new rackets at 42 psi. Suppose the two-tailed P-value for the test described above (obtained from a computer printout) is 0.08. Give the proper conclusion for the test. Use α = 0.05. Group of answer choices Reject H0 and conclude that μ, the true mean tension of the rackets, equals 42 psi. There is sufficient evidence to conclude that μ, the true mean tension of the rackets, is less than 42 psi Accept H0 and conclude that μ, the true mean tension of the rackets, equals 42 psi. There is insufficient evidence to conclude that μ, the true mean tension of the rackets, is less than 42 psi.
- A pharmcuticle company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of Mercury) for 9 patients before taking the new drug and 2 hours after taking the drug are shown in the table below. is there enough evidence support the company's claim? Let D =(blood pressure before taking new drug)- (blood pressure after taking new drug).use significant levels of a=their 0.05 for the test. Assume that the systolic blood pressure levels are normally distributed for the population of patience both Before & After taking the new drug. 1.State the null and alternative hypothesis for the test. 2. Find the value of the standard deviation of the paired differences. Round to one decimal place. 3.compute the value of the test statistic. Round to three decimal places 4.determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion to three decimals. 5.make decision for the hypothesis test.The positive random variable X is said to be a log-normal random variable with parameters μ and σ2 if log(X) is a normal random variable with mean μ and variance σ2. Use the normal moment generating function to find the mean and variance of a lognormal random variable. Hint: Let Y = log(X ) and find E[X ].The contingency table shows the results of a random sample of former smokers by the number of times they tried to quit smoking before they were habit-free and gender. At α=0.10, can you conclude that the number of times they tried to quit before they were habit-free is related to gender? Perform the indicated chi-square independence test by completing parts (a) through (e) below.
- A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 6 new rackets at 68 psi. Suppose the two-tailed P-value for the test described above (obtained from a computer printout) is 0.07 Give the proper conclusion for the test. Use a= 0.05Find the F critical value for 5 degrees of freedom for the numerator, 12 degrees of freedom for the denominator, and 0.025 area in the right tail of the F curve. Note: you can use =FINV(probability, degree of freedom 1, degree of freedom 2) function in Excel to calculate the value for F critical. Select one: a) Fcrit = 3.89 b) Fcrit = 1.54 c) Fcrit = 3.11 d) Fcrit = 2.39A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. to support this claim, the customer asked the pro shop to string 6 new rackets at 68 psi. Suppose the two-tailed p-value for the test described above (obtained from a computer printout) is 0.07. Give the proper conclusion for the test. Use α = 0.05. a) There is sufficient evidence to conclude that μ, the true mean tension of the rackets, is less than 68 psi. b) There is insufficient evidence to conclude that μ, the true mean tension of the rackets, is less than 68 psi. c) Accept H0 and conclude that μ, the true mean tension of the rackets, equals 68 psi. d) Reject H0 and conclude that μ, the true mean tension of the rackets, equals 68 psi.
- Let Z~Normal(0,1). Define X1 = Z and X2 = Z^2. Calculate the Spearman's coefficient of concordance for the pair (X1, X2).Hint 1: For Pearson's correlation coefficient, it is possible to use the property of the symmetry of the normal distribution.symmetry of the normal distribution, or equivalently in terms of calculus, the properties of integrals for odd functions.properties of the integrals for odd functions. In this way, it will not be necessary tosolve integrals that have no solution in the form of an easy-to-work function.Hint 2: The way I found to calculate both Kendall's and Spearman's coefficients was to compute theSpearman coefficients was to calculate the probability P[(X1 - X1′)(X2 - X2′) > 0] and substituting it into theforms equivalent to the definition that come in the book. The one that seems simplest to meis to substitute the X's by their corresponding Z's and use remarkable products to arrive at aprobability in terms of a normal distribution.A local tennis pro-shop strings tennis rackets at the tension (pounds per square inch) requested by the customer. Recently a customer made a claim that the pro-shop consistently strings rackets at lower tensions, on average, than requested. To support this claim, the customer asked the pro shop to string 6 new rackets at 68 psi. Suppose the two-tailed P-value for the test described above (obtained from a computer printout) is 0.07 Give the proper conclusion for the test. Use 0.05 as level of significanceLet Z~Normal(0,1). Define X1 = Z and X2 = Z^2. Calculate the Kendall's matching coefficient. Hint 1: For Pearson's correlation coefficient, it is possible to use the property of the symmetry of the normal distribution.symmetry of the normal distribution, or equivalently in terms of calculus, the properties of integrals for odd functions.properties of the integrals for odd functions. In this way, it will not be necessary tosolve integrals that have no solution in the form of an easy to work with function.