The compound P4S3 is used in matches. It reacts with oxygen to produce P4O10 and SO2. The unbalanced chemical equation is shown below.   P4S3(s) + O2(g) → P4O10(s) + SO2(g)   What mass of SO2 is produced from the combustion of 0.59 g P4S3?   MM of P4S3 = 220.09 g.mol MM of SO2 = 64.07 g/mol   Note: Round off your answer to two decimal places

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Chapter4: Stoichiometry
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The compound P4S3 is used in matches. It reacts with oxygen to produce P4O10 and SO2. The unbalanced chemical equation is shown below.

 

P4S3(s) + O2(g) → P4O10(s) + SO2(g)

 

What mass of SO2 is produced from the combustion of 0.59 g P4S3?

 

MM of P4S= 220.09 g.mol

MM of SO= 64.07 g/mol

 

Note: Round off your answer to two decimal places 

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