The composite A-36 steel bar shown is made from two segments, AB and BD, having cross-sectional areas of AB = 616 mm² and BD = 1243 mm2. Determine the vertical displacement (in mm) of B relative to D. Modulus of Elasticity = 210 GPa. X = 1026 mm, Y = 786 mm, Z= 545 mm NOTE: Input the MAGNITUDE ONLY. Compute and express your final answer in 5 decimal places. 75 kN A 20 KN of 40 kN c 20 kN D X Y 40 KNJ Z

A beam is constructed of two angle sections, each L5 x 3 x 1/2, which reinforce a 2 x 8 (actual dimensions) wood plank (see the cross section shown in the figure). The modulus of elasticity for the wood is E, = 1.2 x 10° psi and for steel is E, = 30 x 10° psi. Assume that the component parts of the beams are securely bonded by adhesives or connected by fasteners. Also, use the transformed-section method in the solutions. 2 x 8 wood plank 5 in 3 in. Steel angles Find the allowable bending moment Mallow for the beam if the allowable stress in the wood is Ow = 1300 psi and in the steel is o = 10,500 psi. Dimensions and properties of the angles: I, = 9.43 in.*, d = 1.74 in. and A, = 3.75 in." (Note: Disregard the weight of the beam). Round your answer to one decimal place. Mallow = k. in.

A composite assembly consisting of a steel [G = 80 GPa] core (2) connected by rigid plates at the ends of an aluminum [G = 28 GPa] tube (1) is shown. The cross-sectional dimensions of the assembly are shown in the second figure. Assume L = 340 mm, D1 = 53, d = 37 mm, d2 = 19 mm. If a torque of T = 1200 N-m is applied to the composite assembly, determine (a) the maximum shear stress in the aluminum tube and in the steel core. (b) the rotation angle of end B relative to end A. (1) T T B L (1) d2 di DI Answers: (a) Talum = i 53.839 MPa Tsteel i 891.026 MPa (b) PB - PA = i 0.02467 rad (2)

Determine the compressive force (in lb) in the bars shown after a temperature rise of 173°F if d = 0.015 in. Round off the final answer to five decimal places. Use the following data: Bronze              Aluminum A = 2.24 sq. in          A = 2.78 sq. in  E = 14959726 psi            E = 10594540 psi L = 12.5 in            L = 16.6 in α = 11.61 x 10-6/ °F      α = 12.67 x 10-6/°F