Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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1. The numerical value of plastic section modulus of the solid rectangular section is
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2. The numerical value of plastic moment of the solid rectangular section is
N.mm
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- = 29,000 For the structure and loading shown below, find the lateral deflection at the top. Use E ksi and I = 250 in4 for all members. Note that in frames, we neglect axial deformation, so you can calculate the deflection at either of the upper corners; the answer will be the same. t. 201 8K 10! 1. What is the deflection at the top in inches (two decimal places) otarrow_forward1. Determine the "t" parameter of cross section of the beam in the figure below (use Navier formula) and the transversal displacement of section A. The allowable stress of the beam material is considered of 100MPa. The cross section of the beam is given in the next figure. q=5KN/m M=4KNm F=3KN L₁=3m L₂=1m L3=1m L1 q A L2 L3 M 8t 2t 2t 10t 2tarrow_forwardFor the beam shown, calculate the bending stress at a point 70 mm. from the top of the beam. P = 59, a = 233, b = 296 Round your answers to 2 decimal places.arrow_forward
- Please answer the following question in the picture and make sure you draw a free body diagram also use positive sign convention for internal forces please, Thank for your help. Post pictures of your work instead of typing it.arrow_forwardA beam of rectangular cross-section 40 x 20 mm is loaded with tensile force 1000 N as shown in figure. A B BO Calculate the shear stress on oblique plane at 0 = 45° A 0.625 MPa C 0.31 MPa F D 1.25 MPaarrow_forwardPart 2,3,4arrow_forward
- In the following structure, determine the stress in each bar. Indicate whether the stress is tensile or compressive. The area of each bar is indicated in this figure. Answ. AB = 8.33 ksi (C), BC = 8.33 ksi (C), DE = 25 ksi (T), AD = 16.6667 ksi (T), BE = 8.33 ksi (T), AE = 27.77 ksi (C)¸ CE = 10.41667 ksi (T).arrow_forwardT·r T (from torsion) = Tr4 J ="- (Solid rod) F Onormal = A o (from bending) M•y - (Solid rod) The solid rod shown in the figure below has diameter of 1.25 in. If it is subjected to the force of 60 lb, determine the state of stress at point A using the principle of superposition. Neglect the weight of the rod, and the stress due to the I %3D I 4 transverse shear force. 60 lb k-10 in.- 15 in. Front View -20 in. Вarrow_forwardDetermine the state of stress acting at point D. Take P₁ = 50 kN and P2 = 10 kN. OD= B ANSWER: P₁ TD= -1.5 m 1.5 m--1.5 m- 0.5 m 40 mm 100 mm 60 mm T D E P₂ 80 mm Part A Find o D. Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. ANSWER: C Q Tap image to zoom Part B Find TD- Express your answer to three significant figures and include the appropriate units.arrow_forward
- Nonearrow_forwardThe frame supports the distributed load shown. Determine the state of stress acting at point E. Show the results on a differential element at this point. The section is composed of two materials where E₁ = 200 GPa, and E₂ = 150 GPa AC xxxx E. 4 kN/m -1.5 m 1.5 m--- -3 m 3 m BA 20 mm 60 mm 20 mm 5 m E 50 mm E₁ = 200 GPa E₂ = 150 GPaarrow_forwardThe plate has a thickness of 20 mm and the force P = 5 kN acts along the centerline of this thickness such that d = 150 mm. (Figure 1) Figure d‡ 200 mm a 1 of 1arrow_forward
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