The car moves along a circular track of radius 9m as shown below: LO It starts with an initial speed v₁=2 m/s at s=0m and increases its speed at a=1m. Determine 1. the velocity of the car when it has travelled a distance s=34 m, this answer must be on your hand-written work. 2. the time needed for the car to travel this distance, this answer must be on your hand-written work. 3. the acceleration of the car at this position, this answer must be on your hand-written work (put it also in the cell bellow)

The car moves along a circular track of radius 9m as shown below: LO It starts with an initial speed v₁=2 m/s at s=0m and increases its speed at a=1m. Determine 1. the velocity of the car when it has travelled a distance s=34 m, this answer must be on your hand-written work. 2. the time needed for the car to travel this distance, this answer must be on your hand-written work. 3. the acceleration of the car at this position, this answer must be on your hand-written work (put it also in the cell bellow)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 6.3t2 - 7.0t and y = 4.3t2 - t°/4.0. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 3.0 s. Answers: When t = 3.0 s, mm/s, i %3D V = mm/s?, 0x = i
• 1. A particle position given by s(t) = 4 t2 - 32 t +36 with s in meters and t in seconds. At what position does the particle come to a # 1 %3D momentary stop to reverse its motion? par • 2. A particle moves in a straight line such that for a short time its velocity is defined by V = ( 4t3 + 3t2 seconds. Determine its position and acceleration when t = 3 s; 2t) ft/s, where t is in %3D %3D he when t = 0, S = 0 %3D e pa he particle for wertical disola reach the ground tance that the paticle travel haght of the paratle, he t lury paricle when the bonzonl distence i 70 m dislmce whn the hayht uf the paricle is %23
Q.1 An object moves along the x-axis according to the equation x (1) =~ 3t +12t 6. where tis in seconds. For the time interval t=0 to t=3 s, (1) find the acceleration: (2) calculate the distance traveled: and (3) determine the displacement of the particle.
a_av = 3.9051 m/s^2
Help me answer this ASAP. Answer it carefully and show complete ans proper solution thank you.
The y-coordinate of a particle in curvilinear motion is given by y = 9.0t³ - 13.3t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 4.3t in./sec². If the velocity of the particle in the x-direction is 12.1 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 3.2 sec. Construct v and a in your solution. Answers: When t = 3.2 sec, V = i in./sec a = in./sec² Mo
Question 7 A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 6.1t2 - 6.1t and y = 6.5t2 - t3/ 2.5. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 3.5 s.Answers: When t = 3.5 s,
A motorcyclist starting from rest travels along a straight road and for 9 s has an acceleration as shown in Figure Q1(b). Draw the v-t graph that describes the Calculate the distance travelled, ST, in t = 9
Example (10): The box slides down the slope described by the equation (y- 0.05 x) m, where is in meters. If the box has x components of velocity and acceleration of vx-3 m/sec and ax- -15 m'sec', at x- Sm, determine the y components of the acceleration of the box at this instant. Homework 2: Complete the solution to find the value of acceleration (ay)? (The answer ay- 0.15 m'sec)
A material point moves along a straight path such that in 2 s it moves from an initial position SA = +0.5 m to a position SB = -1.5 m. Then, in 4 s it moves from the SB position to SC = +2.5 m. With that we will have that the average speed and the average speed of travel of the material point during the time interval 6 s are, respectively: Choose one:a. 1 m / s and 0.333 m / sB. 0.333 m / s and 1 m / sc. both equal to 1 m / sd. 0.4 m / s and 2 m / se. 2 m / s and 0.4 m / s
The formula v = 0.03 t can be used to calculate the tangential acceleration of an automobile moving along a curved path with a radius of curvature of 50 meters. After 10 seconds of travel, calculate the car's velocity and acceleration.
The y-coordinate of a particle in curvilinear motion is given by y = 4.5t3 - 5.9t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 9.6t in./sec2. If the velocity of the particle in the x-direction is 12.9 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 1.4 sec. Construct v and a in your solution.Answers: When t = 1.4 sec,