The boiling point of water is 100.0°C at 1 atmosphere. How many grams of potassium chloride (74.55 g/mol), must be dissolved in 275.0 grams of water to raise the boiling point by 0.450°C? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kp (°C/m) Kf (°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 g potassium chloride.
The boiling point of water is 100.0°C at 1 atmosphere. How many grams of potassium chloride (74.55 g/mol), must be dissolved in 275.0 grams of water to raise the boiling point by 0.450°C? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kp (°C/m) Kf (°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHC13 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 g potassium chloride.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Boiling Point Elevation/Freezing Point Depression
T = m K
where, for freezing point depression:
T = T(pure solvent) - T(solution)
and for boiling point elevation:
T = T(solution) - T(pure solvent)
m | = (# moles solute / Kg solvent) |
Kb | = boiling point elevation constant. |
Kf | = freezing point depression constant. |
Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
Solvent | Formula | Kb(°C / m) | Kf(°C / m) |
Water | H2O | 0.512 | 1.86 |
Ethanol | CH3CH2OH | 1.22 | 1.99 |
Chloroform | CHCl3 | 3.67 | |
Benzene | C6H6 | 2.53 | 5.12 |
Diethyl ether | CH3CH2OCH2CH3 | 2.02 |
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