Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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The bar shown in Figure Q1(a) has a mass of 15 kg and is subjected to a couple moment of M = 70 Nm and a force P = (209) N applied to the end of the bar. The spring has unstretched length of 0.4 m and remain in the vertical position due to roller guide at B. 

URGENT!!! HELP!!

B
1.20 m
k = 40 N/m
P= (200M) N
M=70 N.m
0.70 m
2.0 m
2.5 m
Figure Q1(a)
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Transcribed Image Text:B 1.20 m k = 40 N/m P= (200M) N M=70 N.m 0.70 m 2.0 m 2.5 m Figure Q1(a)
Q1 (a) The bar shown in Figure Q1(a) has a mass of 15 kg and is subjected to a couple
(200M) N applied to the end of the bar. The
moment of M = 70 Nm and a force P
spring has unstretched length of 0.4 m and remain in the vertical position due to roller
guide at B.
Note; Use your last three digit of matrix number to determine the value of force P as
follows;
Example of matrix number, CD190234
M = (2+3+4) = 9
Therefore, P = 200M = 200+9 = 209 N
Draw the free body diagram of the bar to account for all the forces that act on
%D
(i)
it.
(ii)
Determine the total work done by all the forces acting on the bar when it has
rotated downward from 0 = 0° to 0 = 90°.
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Transcribed Image Text:Q1 (a) The bar shown in Figure Q1(a) has a mass of 15 kg and is subjected to a couple (200M) N applied to the end of the bar. The moment of M = 70 Nm and a force P spring has unstretched length of 0.4 m and remain in the vertical position due to roller guide at B. Note; Use your last three digit of matrix number to determine the value of force P as follows; Example of matrix number, CD190234 M = (2+3+4) = 9 Therefore, P = 200M = 200+9 = 209 N Draw the free body diagram of the bar to account for all the forces that act on %D (i) it. (ii) Determine the total work done by all the forces acting on the bar when it has rotated downward from 0 = 0° to 0 = 90°.
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