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P. 10 e- gure P12.19 Problems 19

P. 10 e- gure P12.19 Problems 19

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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rigid body statics

COmponciIUs acting on the bridge at the hinge. Figure P12.19 Problems 19 and 20. Even though this is nominally a formula question, I'm using the numbers in the problem, to help you aim for the book's solution. (I admit that was surprised when I got the book's solution on my first attempt.) One can get lost in hopeless grunge, or even not know how to begin, if one isn't careful. Optimally, one should take vectors seriously with this problem. Put the hinge at the origin, and calculate all torques as T =r x F. Even if you don't for all torques, you really should to get your expression for the torque due to the cable. The tension is parallel to the rope, and the rope's direction is h - c.
Transcribed Image Text:COmponciIUs acting on the bridge at the hinge. Figure P12.19 Problems 19 and 20. Even though this is nominally a formula question, I'm using the numbers in the problem, to help you aim for the book's solution. (I admit that was surprised when I got the book's solution on my first attempt.) One can get lost in hopeless grunge, or even not know how to begin, if one isn't careful. Optimally, one should take vectors seriously with this problem. Put the hinge at the origin, and calculate all torques as T =r x F. Even if you don't for all torques, you really should to get your expression for the torque due to the cable. The tension is parallel to the rope, and the rope's direction is h - c.
eagleom e.nces.cau Do Chapter 12, Problem 11a. (Problem 19a in the 9th ed.) Calculate the tension in the cable, in Newtons. • e = 20° • d = 1 m e = 8 m • M = 2,000 kg • Cable's distance from the hinge (5 m in the text) is c 5 m • h = 12 m • Lot's mass (1000 kg in the text) is m = 1,000 kg 19. Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (Fig. P12.19). Usually, the drawbridge is lowered to a horizontal position so that the end of the bridge rests on the stone ledge. Unfor- tunately, Lost-a-Lot's squire didn't lower the draw- bridge far enough and stopped it at 0 = 20.0° above the horizontal. The knight and his horse stop when their combined center of mass is d = 1.00 m from the end of the bridge. The uniform bridge is l long and has mass 2 000 kg. The lift cable is attached to the bridge 5.00 m from the hinge at the castle end and to a point on the castle wall h = bridge. Lost-a-Lot's mass combined with his armor and steed is 1 000 kg. Determine (a) the tension in the cable and (b) the horizontal and (c) the vertical force %3! 8.00 m 12.0 m above the components acting on the bridge at the hinge.
Transcribed Image Text:eagleom e.nces.cau Do Chapter 12, Problem 11a. (Problem 19a in the 9th ed.) Calculate the tension in the cable, in Newtons. • e = 20° • d = 1 m e = 8 m • M = 2,000 kg • Cable's distance from the hinge (5 m in the text) is c 5 m • h = 12 m • Lot's mass (1000 kg in the text) is m = 1,000 kg 19. Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed (Fig. P12.19). Usually, the drawbridge is lowered to a horizontal position so that the end of the bridge rests on the stone ledge. Unfor- tunately, Lost-a-Lot's squire didn't lower the draw- bridge far enough and stopped it at 0 = 20.0° above the horizontal. The knight and his horse stop when their combined center of mass is d = 1.00 m from the end of the bridge. The uniform bridge is l long and has mass 2 000 kg. The lift cable is attached to the bridge 5.00 m from the hinge at the castle end and to a point on the castle wall h = bridge. Lost-a-Lot's mass combined with his armor and steed is 1 000 kg. Determine (a) the tension in the cable and (b) the horizontal and (c) the vertical force %3! 8.00 m 12.0 m above the components acting on the bridge at the hinge.
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