the ball has a mass of 0.40kg. Intially, it moves horizontally to the left at 20 m/s but then it is kicked and given a velocity with magnitude 30 m/s and direction 45 degrees upward and to the right. find the impulse of the force and the average force on the ball, assuming collision time is 0.010s.

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A: Given data: Mass (m) = 0.2 kg Average force (Fav) = 1000 N Time interval (Δt) = 0.1 s Required:…

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A: We know that  Impulse = change in momentum  Favg×t= change in momentum  Favg=change in momentum/t

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A: Given that, Force (F) = 6N Time (t) = 5 s  Impulse (J) calculated as,  J = F × t    = 6N × 5s   = 30…

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Q: A baseball pitched generates an impulse of 100 Ns. If the contact time between the bat and ball is…

A: Impulse J is defined as; J→=F→∆t∴ F→=J→∆t=100Ns0.005=20000 N Hence the force between the bat and the…

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A: Impulse = change in momentum Impulse = ∆P = m(Vf - Vi)  Force = ∆P/∆t

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A: (a)The net impulse is the area under the curve.The expression for the impulse is,

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