A ball falls from height of 20.0 m, hits the floor, and rebounds vertically upward to height of 15.0 m. Assume that my "ball (a) What is the impulse (in kg. m/s) delivered to the ball by the floor? kg. m/s magnitude direction ---Select--- = 0.385 kg. (b) If the ball is in contact with the floor for 0.0300 seconds, what is the average force (in N) the floor exerts on the ball? N magnitude direction ---Select---

The magnitude of the net force exerted in the x direction on a 3.30-kg particle varies in time as shown in the figure below. F (N) A 2 1 2 3 4 5 4 02 = (a) Find the impulse of the force over the 5.00-s time interval. Ỉ - avg N.S (b) Find the final velocity the particle attains if it is originally at rest. m/s t (s) (c) Find its final velocity if its original velocity is -2.60 î m/s. m/s (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. F II N

(a) What impulse must be imparted to a golf ball of mass 0.045 kg to give it a velocity of 46.5 m/s?(b) If the golf club is in contact with the ball as it is accelerated over an interval of 1.21 cm, estimate the average force exerted on the ball by the club.

Problem 2. A force acts on a 25.0 kg object with the magnitude as a function of time as shown in figure below. (a) Determine the impulse imparted by the force on the object between 0 and 30 seconds. (b) Determine the final velocity of the object if it had an initial velocity of 20.0 m/s in the negative direction. (c) Find the average force between t = 0 and 30 seconds. F,(N) 1000- t (s) 30 0- 10 20