College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Consider a pendulum whose length is 50 ft. What is the formula for the period of oscillation for a pendulum? (Use the following as necessary: L for the length of the pendulum and g for the acceleration of gravity. Do not substitute numerical values; use variables only.) T = 2π₁ X Determine the period in s. 7.8 ✔ S g What is the formula that shows the relationship between the natural frequency and the period of oscillation? (Use the following as necessary: T. Do not substitute numerical values; use variables only.) f = t X Determine the natural frequency in Hz. 0.128 ✔ Hzarrow_forwardIn the figure below, the pendulum consists of a uniform disk with radius r = 34 cm and mass 520 g attached to a uniform rod with length L = 352 mm and mass 207 g. Calculate the period (in seconds) of oscillation. Final answer in four decimal places.arrow_forwardThe oscillatory movement of a simple pendulum is a characteristic of the regular repetition of displacements around an equilibrium position. The pendulum swings due to the restored force of gravity, which seeks to bring the mass back to the equilibrium point. The oscillatory behavior is described by a trigonometric solution, which relates the pendulum's position to time, considering its amplitude, frequency and initial phase. Statement: A simple pendulum moves according to the following question:y(t) = A.sin(ωt + φ)In this question, y(t) is the horizontal position of the pendulum, A is its amplitude, ω is its angular velocity, given by ω = 2πf, and φ is the initial phase of the movement, in radians. Since the initial phase of the movement is equal to 0 and its angular velocity is π/2 rad/s, the oscillation frequency of this pendulum is correctly given by the alternative: a) 2.0Hz b) 1.5Hz c) 1.0Hz d) 0.5Hz e) 0.25Hzarrow_forward
- The angle (with respect to the vertical) of a simple pendulum is given by 0 = 0mcos[(4.64 rad/s)t + p]. If at t = 0,0 = 0.0350 rad and de/dt = -0.200 rad/s, what are (a) the phase constant p and (b) the maximum angle Om? (Hint: Don't confuse the rate de/dt at which 0 changes with the w of the SHM.) Pivot point | s= L0 F,cose Fgsine- (a) (b) (a) Number i Unit (b) Number Unitarrow_forwardA oscillation is described by the following function of velocity against time: v(t) = (3.2 m/s) sin [(21.2 rad/s)f] What is this oscillator's amplitude, in meters? Answerarrow_forwardCalculate the period of oscillation of a pendulum on a planet of density pp = 10³ kg m-³ with radius Rp = 3.9 x 10³ km, while period of the same pendulum on Earth is TE= 1.3 s. Assume the Earth to be a sphere of radius RE = 6.4 x 10³ km and density of pe = 5.5 x 10³ kg m-³. Give your answer in Sl units. Answer: S ◆arrow_forward
- In the physics Lab, you measure a max speed of the pendulum of 0.55m/s. If the maximum deflection angle is 8 degrees, what is the pendulum's length?arrow_forwardHow long must a simple pendulum be if it is to make exactly one swing per seven seconds? (That is, one complete oscillation takes exactly 14 s.)arrow_forwardThe angle (with respect to the vertical) of a simple pendulum is given by 0 = 0mcos[(5.88 rad/s)t + p]. If at t = 0,0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which 0 changes with the w of the SHM.) %3D Pivot point S= Le F,cose Fgsine- (a) (b) (a) Number i Unit (b) Number i Unit >arrow_forward
- A pendulum has a period of 5.8 s. If you were to transfer this pendulum to the surface of Mars (where g is 3.71 meters per second squared), what would the period (in seconds) be?arrow_forwardA 236 g ball is tied to a string. It is pulled to an O angle of 7.8 and released to swing as a pendulum. A student with a stopwatch finds that 13 oscillations take 18 s. You may want to review (Pages 405 - 407). How long is the string? Express your answer to two significant figures and include the appropriate units. L = μÅ Value Ć Units ?arrow_forwardThe angle (with respect to the vertical) of a simple pendulum is given by 0 = 0mcos[(5.88 rad/s)t + ø]. If at t = 0, 0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle 0m? (Hint: Don't confuse the rate d0/dt at which 0 changes with the w of the SHM.) %3D Pivot point L. Is= Le F.cose Fg sine (a) (6)arrow_forward
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