Calculate the period of oscillation of a pendulum on a planet of density pp = 10 kg m with radius Rp = 3.9 x 10' km, while period of the same pendulum on Earth is T=1.2s. Assume the Earth to be a sphere of radius Rp = 6.4 x 10 km and density of pE = 5.5 x 10' kg m3. Give your answer in SI units. Answer: Choose.. Next page

A pendulum is released at an angle of 5.0°, and you measure the period (T) of the pendulum to be 2.0 sec. If the angle of the same pendulum is increased to 10.0° what will be the new period (T) of the pendulum?

The relation between gravitational acceleration and period for a 1.0-m long 1 pendulum is , where 7 is the period in seconds and & represents the 2 ng %3D gravitational acceleration in metres per second squared (m/s2). a) The gravitational acceleration at the surface of Earth is about 9.8 m/s2. Find the period of a pendulum 1.0 m long. b) The gravitational acceleration on the moon is approximately of the gravitational 1 acceleration at the surface of Earth. Determine the period of a pendulum 1.0 m long on the moon. c) Captain Mirk and Mr. Spark land on one of seven planets in the Alpha Beta system. Mr. Spark sets up a pendulum 1.0 m long, and Captain Mirk measures its period to be 1.304 s. Use the table to help you determine which planet they are on. Planet Ulu 3.6 Proserpine Wunderland Rutabaga Ada Sirius-Lee Ikona 6.8 13.5 19.7 23.2 31.1 54.0

Ten measurements of the period of a simple pendulum were as follows: 2.13 s, 2.07 s, 2.24 s, 2.20 s, 2.08 s, 2.11 s, 2.15 s, 2.19 s, 2.22 s, 2.16 s  (1) Calculate the standard deviation (SD) of the measurement results, and the standard error which is given by:standard error = SD/n

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The period of a simple pendulum (T) is measured as a function of length (L) on an unknown planet. The dependence of of L is linear (see the graph below). Use the slope of this graph to calculate the acceleration of gravity on this planet, in m/s2. 0.25 y = 0.0909x 0.2 0.15 0.1 0.05 Plot Area 0.5 1 1.5 2 2.5 L (m) T?/4 pi?(s')