The amplifier shown below has a variable gain control, using a potentiometer for RE with the wiper ac- grounded. As the potentiometer is adjusted, more or less of Re is bypassed to ground, thus varying the gain. The total Re remains constant to dc, keeping the bias fixed. If a load resistance R₁ of 600 2 is placed on the output of the amplifier, what will be the value of RE for the voltage gain (50)? Neglect the output resistance to of the transistor. RE C₁ 10μF R₁ ww R₂ 3.3 M Vec +8V Rc 330 f C₂ 10 F Poc= 150 100 £2 -C₂₁₂ 100 F

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The amplifier shown below has a variable gain control, using a potentiometer for RE with the wiper ac-
grounded. As the potentiometer is adjusted, more or less of Re is bypassed to ground, thus varying the gain.
The total RE remains constant to dc, keeping the bias fixed. If a load resistance R₁ of 600 2 is placed on the
output of the amplifier, what will be the value of RE for the voltage gain [50]? Neglect the output resistance To
of the transistor.
RE
Vo
C₁
H
10 μF
R₁
12 k
ww
R₂
3.3 kl
Vec
+8 V
www.
Rc
330 2
C₂
Hor
10 μF
Poc 150
R₂
100 f
C₂
100 μF
Transcribed Image Text:The amplifier shown below has a variable gain control, using a potentiometer for RE with the wiper ac- grounded. As the potentiometer is adjusted, more or less of Re is bypassed to ground, thus varying the gain. The total RE remains constant to dc, keeping the bias fixed. If a load resistance R₁ of 600 2 is placed on the output of the amplifier, what will be the value of RE for the voltage gain [50]? Neglect the output resistance To of the transistor. RE Vo C₁ H 10 μF R₁ 12 k ww R₂ 3.3 kl Vec +8 V www. Rc 330 2 C₂ Hor 10 μF Poc 150 R₂ 100 f C₂ 100 μF
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