The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion? H Click on the icon to view the data table. What is the value of the test statistic for this test? O A. F= (Round to two decimal places as needed.) O B. In this case, the test for the effect from a row factor should not be done. What is the corresponding P-value of the test statistic, F, for this test? O A. P-value = (Round to three decimal places as needed.) O B. In this case, the test for the effect from a row factor should not be done. State the conclusion of this test. Choose the correct answer below. O A. Do not reject Ho. There is insufficient evidence to warrant rejection of the claim that the row values are from populations with the same mean. O B. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the row values are from populations with the same mean. OC. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the row values are from populations with the same standard deviation. O D. Do not reject Ho. There is insufficient evidence to warrant rejection of the claim that the row values are from populations with the same standard deviation. O E. In this case, the test for the effect from a row factor should not be done. State the null and alternative hypotheses in the test for the effect from the column factor.

Minutes 28 24 37 32 34 32 31 34 25 23 32 24 23 39 24 40 23 35 31 26 27 36 27 21 25 34 24 33 28 27 38 35 36 28 36 38 34 33 32 30 31 30 30 19 30 24 28 22 30 21 21 28 33 24 39 38 27 35 34 28 18 19 29 31 38 28 33 22 25 49 24 33 21 38 31 32 26 31 33 30 32 31 31 31 39 34 39 28 32 36 30 29 29 27 24 34 26 20 32 32 34 25 21 32 37 28 25 22 41 28 Above is the excel data and use excel to solve with explanation and write a conclusion at the end, thanks

Minutes 28 24 37 32 34 32 31 34 25 23 32 24 23 39 24 40 23 35 31 26 27 36 27 21 25 34 24 33 28 27 38 35 36 28 36 38 34 33 32 30 31 30 30 19 30 24 28 22 30 21 21 28 33 24 39 38 27 35 34 28 18 19 29 31 38 28 33 22 25 49 24 33 21 38 31 32 26 31 33 30 32 31 31 31 39 34 39 28 32 36 30 29 29 27 24 34 26 20 32 32 34 25 21 32 37 28 25 22 41 28 USE EXCEL with explanation please

Age at death of 25 people as follows. 78 90 82 90 79 83 88 94 98 77 87 74 77 92 91 79 68 94 77 96 94 76 77 92 85

9 33 56 75 98 45 67 51 41 30 11 10 29 26 35 33 53 64 79 41 87 84 20 21 43 75 56 68 42 23 38 41 69 61 31 52 66 76 54 93 48 64 43 55 78 49 63 58 48 31 35 57 51 87 33 37 58 59 72 43 17 21 27 34 44 65 53 43 30 25 86 88 20 22 30 55 69 71 56 83 39 40 68 60 77 55 61 48 48 37 69 40 53 58 31 56 77 55 73 45 (a) Calculate the relative, percentage, and cumulative frequencies of the data set. (b) Draw the calculated frequencies as boxes and pie graphs and determine the shape of the bar diagram. (c) Calculate the average, median, mode, range, variance, and standard deviations of both the population and the sample set.

The accompanying data are 45 commute times to work in minutes for workers of age 16 or older in Chicago. Construct a frequency distribution. Use a class width of 15 minutes and begin with a lower class limit of 0 minutes. Do the data amounts appear to have a normal distribution? Examine the data and identify anything appearing to be unique. Click the icon to view the commute times. Construct the frequency distribution. Commute Time (minutes) Frequency 0-14 4 15-29 15 30-44 11 45-59 60-74 9 5 75-89 (Type whole numbers.) Do the data amounts appear to have a normal distribution? A. No, because while the distribution is approximately symmetric, the frequencies start at a maximum and become low. B. No, because while the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, the distribution is not symmetric. OC. Yes, because the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, and the distribution is…

Student  ID Math Score Project Score Age (years) Sex 001254 52 75 15 M 003256 78 89 15 F 001547 92 82 18 F 012589 91 66 17 M 021475 72 93 14 M 032658 46 76 13 M 009561 68 76 14 F 008654 52 82 12 F 008561 83 75 16 M 003547 45 78 14 F 047452 73 96 14 M 041212 64 79 13 F 032320 41 67 13 F 000258 77 72 15 F 001478 82 75 17 M 019521 59 83 15 M 017451 80 71 17 F 016335 48 76 13 M 002474 57 80 14 F 095844 97 71 18 F 097304 86     86 17 M 090024 75 85 15 F 034702 81 80 16 F 001910 67 74 14 F 006454 86 77 17 M 087478 63 82 13 M 078474 68 79 14 F 000977 54 89 12 M 063010 91 73 18 M 007406 46 77 15 F 025740 93 85 17 M…

Student  ID Math Score Project Score Age (years) Sex 001254 52 75 15 M 003256 78 89 15 F 001547 92 82 18 F 012589 91 66 17 M 021475 72 93 14 M 032658 46 76 13 M 009561 68 76 14 F 008654 52 82 12 F 008561 83 75 16 M 003547 45 78 14 F 047452 73 96 14 M 041212 64 79 13 F 032320 41 67 13 F 000258 77 72 15 F 001478 82 75 17 M 019521 59 83 15 M 017451 80 71 17 F 016335 48 76 13 M 002474 57 80 14 F 095844 97 71 18 F 097304 86     86 17 M 090024 75 85 15 F 034702 81 80 16 F 001910 67 74 14 F 006454 86 77 17 M 087478 63 82 13 M 078474 68 79 14 F 000977 54 89 12 M 063010 91 73 18 M 007406 46 77 15 F 025740 93 85 17 M…

Student  ID Math Score Project Score Age (years) Sex 001254 52 75 15 M 003256 78 89 15 F 001547 92 82 18 F 012589 91 66 17 M 021475 72 93 14 M 032658 46 76 13 M 009561 68 76 14 F 008654 52 82 12 F 008561 83 75 16 M 003547 45 78 14 F 047452 73 96 14 M 041212 64 79 13 F 032320 41 67 13 F 000258 77 72 15 F 001478 82 75 17 M 019521 59 83 15 M 017451 80 71 17 F 016335 48 76 13 M 002474 57 80 14 F 095844 97 71 18 F 097304 86     86 17 M 090024 75 85 15 F 034702 81 80 16 F 001910 67 74 14 F 006454 86 77 17 M 087478 63 82 13 M 078474 68 79 14 F 000977 54 89 12 M 063010 91 73 18 M 007406 46 77 15 F 025740 93 85 17 M…

Find P95  from the following data 1 5 8 14 21 22 23 25 26 28 30 31 34 39 40 42 43 49 53 56 59 62 64 69 72 75 77 78 79 81 83 92 94 97 100 P95 =