The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferroni test with the sample data. Complete parts (a) through (c). H Click the icon to view the data table of the poplar weights and the Bonferroni results. - X Poplar weights (kg) and bonferroni results a. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight. Determine the null and alternative hypotheses. No Treatment Fertilizer Irrigation Fertilizer and Irrig Họ 1.15 0.99 0.06 0.87 0.46 0.72 0.63 1.88 0.48 0.49 0.07 1.51 Find the test statistic. 0.17 0.49 0.82 2.37 (Round to two decimal places as needed.) 1.31 1.02 0.88 1.76 Find the P-value. Bonferroni Results Mean Difference (I-J) Std. Error - 0.0280 P.value = (Round to three decimal places as needed.) (1) TREATMENT 1.00 (J) TREATMENT 2.00 Sig. 1.000 0.24013 0.24013 What is the conclusion for this hypothesis test? 0.2220 – 0.9640 3.00 1.000 4.00 0.24013 0.019 O A. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. O B. Fail to reject Ho There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OC. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. O D. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. Drint Dene

Claim: : P = 0.23; a 0.10; Sample Statistics : P = 0.17₁ n = 100 A.) Find the 2- test static. Select the Correct Choice below and, if necessary, fill in the answer box to Complete Your choice. 2 = ( Round to two decimal places as needed) 0 3.) What is the result of the test Reject or fail to reject? ?

J In-shop othesis test for the difference between two population proportions 02562 2600368.qx3zqy7 Jump to level 1 The manager of a coffee shop is trying to determine if drive-through customers buy fewer items than customers who come into the shop. The manager randomly samples both populations and calculates the proportion of customers in each that buy three or more items. The results of the data collected are shown below. What are the population parameters? Y Pick Drive-through Successes 27 Successes What is the level of significance? Ex: 0.12 Observations 76 Observations 41 119 0.345 p-hat_1 0.355 p-hat_2 What is the null hypothesis Ho? Pick Confidence Level 0.1429 What is the alternative hypothesis Ha? Pick p-value Should Ho be rejected or does Ho fail to be rejected? Pick What conclusion can be drawn from the data? Pick evidence exists to support the claim that drive-through customers buy fewer items than in-shop customers. 2 p W

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