Problem 22.77The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t) N,where t is in seconds. (Figure 1)Figurek = 400 N/mWWWk = 400 N/mO 020 kgOOOOF90 cos 6trCc = 125 N.s/m1 of 1Part AWrite the equation which describes the steady-state motion.Express your answer in terms of t. Express your answer using three significant figures. Express the phase in radians and the final result in meters.x =Submit15. ΑΣΦΑProvide FeedbackRequest Answervec?m

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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The 20-kg block is subjected to the action of the harmonic force F = (90 cos 6t) N, where t is in seconds. (Figure 1) Figure k= 400 N/m k = 400 N/m O 20 kg F= 90 cos 6t 125 N.s/m 1 of 1 Part A Write the equation which describes the steady-state motion. Express your answer in terms of t. Express your answer using three significant figures. Express the phase in radians and the final result in meters. x = Submit 17 ΑΣΦ Provide Feedback ↓↑ Request Answer vec ? m Next >
When a 5000 lb car driven at 60 mph on a level road is suddenly put into neutral gear (i.e. allowed to coast), the velocity decreases in the following manner: 60 V = mph , 1+() where t is the time in sec. Find the horsepower required to drive this car at 30 mph on the same road. Useful constants: 9 = 22 mph/sec, 1 H.P. = 550 ft.lb/sec, 60 mph = 88 ft/sec.
F W spring 0.5 Wtotal S N m A block of a mass of 6 kg and a spring with a k value 30 as shown in the diagram shown below. The kinetic μ has a value of μ = 0.2 the applied force F = 60 N. Assume the block is already in motion (only use kinetic coefficient) and there more the spring is already compressed by 0.5 m. What is the magnitude of work done by force, spring, and total work after the system comes to an equilibrium? UBC Engineering Please consider whether the work is positive or negative work and include the correct sign in your answer below W force
d2 d₁ A Ad₁ VA = A small cylinder with a weight of 10 lb is dropped from an initial height of d₂: 3 ft from rest. The spring has an unstretched length of lo = 12 inches and a spring constant of k = 30 lb\inch. The spring is intially compressed by small ropes to a length d₁ = 6 inches. = k What is the maximum additional distance the spring compresses after the cylinder lands on the platform? Assume the platform and spring are massless in this calculation. inches
Q1. Consider the belt and pulley system in the figure below. Inertias other than that shown in the figure are negligible. The pulley radius r= 9 cm, and the motor inertia Jm = 0.01 kg m. Calculate the torque Tm required to accelerate a load of mass I kg from rest to a speed of I m/s in a time interval of 4 seconds. Assume the motor torque to be constant during this interval. Tm Motor (Figure P-12 on page 376 from Mohan's Book)
In the system shown in the figure, mA = 2 kg and mB = 5 kg.the mass is connected to each other by rope. A 12 N Fforce is applied to body A at an angle of 10 °.There is only friction between body B and the inclined planeand the kinetic coefficient of friction is 0.3. a) Draw the free body diagram of each object. b) Find the acceleration of the system. g = 9.8 m / s ^ 2, sin (37 °) = cos (53 °) = 0.60, cos (37 °) = sin (53 °) = 0.80, sin (10 °) = 0.17,cos (10 °) = 0.98
m = 160 gram 3. What is the change in length of the three springs? Acceleration due to gravity is g = 10 m.s³². 4. A bullet m = 0.001 kg moves with a speed of 500 m/s and strikes a After the collision the bullet becomes embedded into the block. Th the end of a spring k = 120 N/m. m M K mind k₁ relele mmm 2 kg a. What is the initial kinetic energy of the bullet? b. What is the speed of the bullet-block system after the collision? c. What is the kinetic energy of the bullet-block system after the collision? d. What is the maximum elastic potential energy when the block comes to rest? helele k₂
Khufra works at a spring factory and he was assigned to test a certain spring, whose constant is 50 N/m attached to a 50-kg block in an incline (©=30°). With the spring initially at equilibrium position, the block was pushed 0.3 meters up the incline by a 50-N external force applied parallel to the path. The coefficient of kinetic friction is 0.30. d) How much work is done by the block (in Joules) on the spring? e) How much work is done by the applied push on the block? f) How much work is done by friction?
The figure shown below is released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. For the values given below answer the following questions:Position 1 is Ha1 μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the Gravitational Potential Energy for mass mA at position 1 (remember your signs)? What is the Gravitational Potential at position 1 for mB? What is the Potential Energy of the spring at position 1? What is the Kinetic Energy at position 1 for mA? What is the Kinetic Energy at position 1 for mB? Again we have the figure shown below that was released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. At position 2 the spring is at its max stretch. Remember we have the values below; answer the following questions: μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the max stretch in the spring?
6. A 12 lb. weight stretches a spring 2 feet. The mass-spring system is immersed in a medium offering resistance that is numerically equal to one quarter of the instantaneous velocity. The weight is released from a point 1 foot below equilibrium. Find its position at any future time.
Q1 ( k₁=1500 N m For the system shown in Figure 1, m₁= 35 kg, m₂ = 20 kg, N and k₂=2000. If the initial displacement and velocity of mass m² m m is x₁0=12 mm and v10=0 and the initial displacement and velocity of mass m² is x20=-6 mm and v20=0 find the resulting motion of the two masses. S m S m₁ m2 Figure 1 X₁ (t) X₂(t)
Q- A block of mass 100 kg is attached to springs of spring constant K₁ = 40 N/m and K₂ = 60 N/m. The block is displaced to the left through a distance of 2.5 m. The speed of the block when it passes through it's original position is _m/sec.

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