Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho: p=0.5 versus H₁: p > 0.5 n = 250; x = 145; α = 0.1 Click here to view page 1 of the table. Click here to view page 2 of the table. Calculate the test statistic, Zo Zo (Round to two decimal places as needed.) - ***

State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t = -2.272 (b) t = 2.154 (c) t = 2.303 (d) t= -2.301 -to = -2.226 to = 2.226

Ho;p=0.77 H1;p>077 your sample consists of 136 subjects, with 100 sucesses calculate the t statistics rounded to 2 decimal places

A large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period.   Single Policyholders Married Policyholders  n1=550  n2=1,000 Number making claims = 110 Number making claims = 150   a. Use a=0.05 Test to determine whether the claim rates differ between single and married male policyholders. z-value  (to 2 decimals) p-value  (to 4 decimals)   b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number. (  ,   )

Use the data below to test the claim that the weight loss was greater with the low fat diet compared to the low carbohydrate diet.  Use a 10% level of significance. Low Fat Low Carbohydrate x¯1=3.9lbs s1=4.2lb n1=51 x¯1=2.6lb s1=5.9lb n1=79    Identify the tail of the test                                   What is the P-value?                                 Will the null hypothesis be rejected?                                     Is the initial claim supported?

H0: μ ≤ 16.09 vs. HA: μ > 16.09What is the test statistic for sample of size 25, mean 13.97,and standard deviation 1.48?

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The test statistic for Ho: p = 0.75 versus HA: p > 0.75 is z = -3.05. What is the p-value for this test? Round to four decimal places. p-value

Claim: Most adults would erase all of their personal information online if they could, A software firm survey of 586 randomly selected adults showed that 61% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is. (Round to two decimal places as needed.)

help solve attached, and following parts pertaining to attached image, all parts please. find test statisitic t find p value State the conclusion for the test. A. Reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda. Your answer is not correct.   B.Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.   C. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.   D.Reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.   b. Construct a confidence…