MATLAB: An Introduction with Applications
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ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 65 cities is 2.39 parts per million and the standard deviation is 2.11 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed.arrow_forwardnutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 90 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.02 pounds. At α=0.03, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: μ=3.4 Ha: μ≠3.4 Your answer is correct. B. H0: μ>3.4 Ha: μ≤3.4 C. H0: μ≤3.3 Ha: μ>3.3 D. H0: μ≤3.4 Ha: μ>3.4 E. H0: μ>3.3 Ha: μ≤3.3 F. H0: μ≠3.3 Ha: μ=3.3 (b) Identify the standardized test statistic. z=negative 0.93−0.93 (Round to two decimal places as needed.) (c) Find the P-value. 0.3520.352 (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis.arrow_forwardCarboxyhemoglobin is formed when hemoglobin is exposed to carbon monoxide. Heavy smokers tend to have a high percentage of carboxyhemoglobin in their blood.t Let x be a random variable representing percentage of carboxyhemoglobin in the blood. For a person who is a regular heavy smoker, x has a distribution that is approximately normal. A random sample of n = 12 blood tests given to a heavy smoker gave the following results (percent carboxyhemoglobin in the blood). Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this choice of d.f. may increase the P-value a small amount and thereby produce a slightly more "conservative" answer. 9.1 9.8 10.4 9.8 11.3 12.2 11.6 10.3 8.9 9.7 13.4 9.9 (a) Use your calculator to calculate x and s. (Round your answers to four decimal places.) X = S = (b) A long-term population mean u = 10% is considered a health risk. However, a long-term population mean above 10% is considered a…arrow_forward
- Part C. To reduce the percentage of defective chips the company...arrow_forwardHn. Don't provide handwriting solutionarrow_forwardA normal population has mean =μ9 and standard deviation =σ5 . Find the proportion of the population that is greater than 4 . Round the answers to at least four decimal places. The proportion of the population that is greater than 4 is .arrow_forward
- Medical Operations The director of a medical hospital feels that her surgeons perform fewer operations per year than the national average of 211. She selected a random sample of 15 surgeons and found that the mean number of operations they performed was 210.6. The standard deviation of the sample was 3.8. Is there enough evidence to support the director's feelings at =α0.10? Assume that the population is approximately normally distributed. Use the critical value method and tables.a. State the hypotheses and identify the claim H0= (claim or not claim) H1= (claim or not claim) This hypothesis test is a (one tailed or two tailed) test Critical value(s)= t= (Reject or do not reject) the null hypothesis is there enough evidence to support the claim?arrow_forwardAnswer the exercise of the image. (In the other image are the final answers, this to verify the final answer).arrow_forwardNewspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. (a) State the hypothesis and identify the claim with the correct hypothesis. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to 2 decimal places, if necessary. Critical values: (c)Compute the test value. Round the answer to at least 2 decimal places, if necessary. z= (d)Make the decision.…arrow_forward
- Test a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 64 cities is 2.38 parts per million and the standard deviation is 2.11 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. Question content area bottom Part 1 (a) Identify the claim and state H0 and Ha. Which of the following correctly states H0 and Ha? H0: ▼ sigmaσ muμ sigma squaredσ2 pp ▼ greater than or equals≥ not equals≠ equals= greater than> less than< less than or equals≤ enter your response here Ha: ▼ pp muμ sigmaσ sigma squaredσ2 ▼ greater than or equals≥ not equals≠ greater than> less than or equals≤ less than< equals= enter your response here (Type integers or decimals. Do not round.) The claim…arrow_forwardTest a claim that the mean amount of carbon monoxide in the air in U.S. cities is less than 2.33 parts per million. It was found that the mean amount of carbon monoxide in the air for the random sample of 66 cities is 2.38 parts per million and the standard deviation is 2.12 parts per million. At α=0.01, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed.arrow_forward
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