A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At α=0.05, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: μ=900 Ha: μ≠900 (claim) B. H0: μ≤880 Ha: μ>880 (claim) C. H0: μ≤900 Ha: μ>900 (claim) D. H0: μ>880 (claim) Ha: μ≤880 E. H0: μ>900 (claim) Ha: μ≤900 F. H0: μ=880 (claim) Ha: μ≠880 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is nothing. B. The critical values are ±nothing. Identify the rejection region(s). Select the correct choice below. A. The rejection regions are z<−1.64 and z>1.64. B. The rejection region is z<1.64. C. The rejection region is z>1.64. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=nothing. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. A. Reject H0 because the standardized test statistic is in the rejection region. B. Reject H0 because the standardized test statistic is not in the rejection region. C. Fail to reject H0 because the standardized test statistic is not in the rejection region. D. Fail to reject H0 because the standardized test statistic is in the rejection region. (e) Interpret the decision in the context of the original claim. At the 5% significance level, there ▼ isis is notis not enough evidence to ▼ support reject the claim that the mean monthly residential electricity consumption in a certain region ▼ is less than is greater than is different from nothing kWh. Click to select your answer(s).

A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 63 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At α=0.05, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: μ=900 Ha: μ≠900 (claim) B. H0: μ≤880 Ha: μ>880 (claim) C. H0: μ≤900 Ha: μ>900 (claim) D. H0: μ>880 (claim) Ha: μ≤880 E. H0: μ>900 (claim) Ha: μ≤900 F. H0: μ=880 (claim) Ha: μ≠880 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is nothing. B. The critical values are ±nothing. Identify the rejection region(s). Select the correct choice below. A. The rejection regions are z<−1.64 and z>1.64. B. The rejection region is z<1.64. C. The rejection region is z>1.64. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=nothing. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. A. Reject H0 because the standardized test statistic is in the rejection region. B. Reject H0 because the standardized test statistic is not in the rejection region. C. Fail to reject H0 because the standardized test statistic is not in the rejection region. D. Fail to reject H0 because the standardized test statistic is in the rejection region. (e) Interpret the decision in the context of the original claim. At the 5% significance level, there ▼ isis is notis not enough evidence to ▼ support reject the claim that the mean monthly residential electricity consumption in a certain region ▼ is less than is greater than is different from nothing kWh. Click to select your answer(s).

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Question

A company claims that the mean monthly residential electricity consumption in a certain region is more than

880

kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of

residential customers has a mean monthly consumption of

900

kWh. Assume the population standard deviation is

121

kWh. At

α=0.05,

can you support the claim? Complete parts (a) through (e).

(a) Identify

and

Ha.

Choose the correct answer below.

H0:

μ=900

Ha:

μ≠900

(claim)

H0:

μ≤880

Ha:

μ>880

(claim)

H0:

μ≤900

Ha:

μ>900

(claim)

H0:

μ>880

(claim)

Ha:

μ≤880

H0:

μ>900

(claim)

Ha:

μ≤900

H0:

μ=880

(claim)

Ha:

μ≠880

(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.

(Round to two decimal places as needed.)

The critical value is

nothing.

The critical values are

±nothing.

Identify the rejection region(s). Select the correct choice below.

The rejection regions are

z<−1.64

and

z>1.64.

The rejection region is

z<1.64.

The rejection region is

z>1.64.

The standardized test statistic is

z=nothing.

(Round to two decimal places as needed.)

(d) Decide whether to reject or fail to reject the null hypothesis.

Reject

because the standardized test statistic

in the rejection region.

Reject

because the standardized test statistic

is not

in the rejection region.

Fail to reject

because the standardized test statistic

is not

in the rejection region.

Fail to reject

because the standardized test statistic

in the rejection region.

(e) Interpret the decision in the context of the original claim.

At the

significance level, there

▼

isis

is notis not

enough evidence to

▼

support

reject

the claim that the mean monthly residential electricity consumption in a certain region

▼

is less than

is greater than

is different from

nothing

kWh.

Click to select your answer(s).

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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