What is the cell potential (E) for a galvanic cell formed from the following two half-reactions? Assume that the celltemperature is 38°C and the operating pressure is 0.04 atm.Cd2*(aq) + 2 e- → Cd(s);[Cd2*] = 0.50 ME° = -0.403 VMg2*(aq) + 2 e- → Mg(s);[Mg*] = 2.75 ME° = -2.37 VA) 1.90 VB) 1.95 V1.99 VD) 2.20 V

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temperature is 38°C and the operating pressure is 0.04 atm. Cd2*(aq) + 2 e- → Cd(s); [Cd²*] = 0.50 M E° = -0.403 V Mg2*(aq) + 2 e- → Mg(s); [Mg2+] = 2.75 M E° = -2.37 V A) 1.90 V B) 1.95 V c) 1.99 V D) 2.20 V

temperature is 38°C and the operating pressure is 0.04 atm. Cd2(aq) + 2 e- → Cd(s); [Cd²] = 0.50 M E° = -0.403 V Mg2*(aq) + 2 e- → Mg(s); [Mg2+] = 2.75 M E° = -2.37 V A) 1.90 V B) 1.95 V c) 1.99 V D) 2.20 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

What is the cell potential (E) for a galvanic cell formed from the following two half-reactions? Assume that the cell
temperature is 38°C and the operating pressure is 0.04 atm.
Cd2*(aq) + 2 e- → Cd(s);
[Cd2*] = 0.50 M
E° = -0.403 V
Mg2*(aq) + 2 e- → Mg(s);
[Mg*] = 2.75 M
E° = -2.37 V
A) 1.90 V
B) 1.95 V
1.99 V
D) 2.20 V

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