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Tatuo Aida investigated the genetic basis of color variation in the medaka (Aplocheilus latipes), a small fish found in Japan (T. Aida. 1921. Genetics 6:554–573). Aida found that genes at two loci (B, b and R, r) determine the color of the fish: fish with a dominant allele at both loci (B_ R_) are brown, fish with a dominant allele at the B locus only
(B_ rr) are blue, fish with a dominant allele at the R locus only (bb R_) are red, and fish with recessive alleles at both loci (bb rr) are white. Aida crossed a homozygous brown fish with a homozygous white fish. He then backcrossed the F1 with the homozygous white parent and obtained 228 brown fish, 230 blue fish, 237 red fish, and 222 white fish.
Q. Use a chi-square test to compare the observed numbers of backcross progeny with the number expected. What conclusion can you make from your chi-square results?
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- In the yawncat (a rare hypothetical animal), the dominant allele R causes solid tail color, and the recessive allele r results in white spots on a colored background. The black coat color allele B is dominant to the brown allele b, but the B and b alleles can only be expressed if the animal has an mm genotype at a third gene locus. Animals that are M_ are yellow regardless of which allele from the B locus is present. A mating between a solid yellow-tailed male yawncat and a solid brown-tailed female yawncat produces 16 offspring with the following tail phenotypes: six solid yellow, two spotted yellow, three solid black, one spotted black, three solid brown, and one spotted brown. What is the probability of the next offspring from these same two parents having a spotted brown tail? O A. 1/16 B. 9/16 С. 3/16 D. 1/2 O E. 1/4arrow_forwardPink eye and albinism are two recessive traits found in the deer mouse, Peromyscus maniculatus. In mice with pink eye, the eye is devoid of color and appears pink from the blood vessels within it. Albino mice are completely lacking color both in their fur and in their eyes. F. H. Clark crossed pink‑eyed mice with albino mice; the resulting F1 had normal coloration in their fur and eyes. He then crossed these F1 mice with mice that were pink‑eyed and albino and obtained the mice shown in the table below. It is very hard to distinguish between mice that are albino and mice that are both pink‑eyed and albino, so he combined these two phenotypic classes (F. H. Clark, 1936, Journal of Heredity 27:259−260). Match the expected numbers of progeny with each phenotype if the genes for pink‑eye and albinism assort independently. Phenotype Observed Expected wild type, wild type 12 wild type, pink eyes 62 albino, wild type, or pink eyes 78 Total 152 152 Answer…arrow_forwardIn cats, white patches are caused by the dominant allele P while p/p individuals are solid colored. Short hair is caused by the dominant allele S, while s/s cats have long hair. A longhaired cat with patches whose mother was solid-colored and shorthaired mates with a shorthaired, solid-colored cat whose mother was longhaired and solid-colored. What kinds of kittens can arise from this mating and in what proportions? Outline the cross and assign genotypes, phenotypes, and proportions in the space below. Plong hair, white patchesxshort hair, solid colored s/s ; P/pS/s ; p/p F1 progeny: 1/4 s/s ; P/plong hair, white patches 1/4 s/s ; p/plong hair, solid colored 1/4 S/s ; P/pshort hair, white patches 1/4 S/s ; p/pshort hair, solid coloredarrow_forward
- In a newly discovered species of Giant Pacific Octopus, long tentacles (L) are dominant to short tentacles (l), strong suction cups (S) are dominant to weak suction cups (s), and brown body color (B) is dominant to red body color (b). A trihybrid test cross was performed between male octopuses that were heterozygous for all three genes, and female octopuses that were homozygous recessive. (You may assume that the dominant alleles exhibit complete dominance.) The results of this cross are shown in the table attached Please complete the table and answer the following questions: a) Are these genes linked? Explain why you think these genes are linked or unlinked? b) What is the genotype of each of the two parents that produced the offspring shown in the data table? Please indicate the linkage phase as you write the genotype of each parent. (Please write the genotypes in the format: xyz/xyz.) Genotype of male parent octopus: Genotype of female parent octopus:arrow_forwardIn chickens, comb shape is determined by genes at two loci (Gene 1 has alleles R, r and Gene 2 has alleles P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_P). The genotype R_pp gives a rose comb phenotype; rrP_gives a pea comb phenotype; and rrpp gives a single comb phenotype. Based on this information give specific genotypes for comb shape of the parents in the crosses listed below: A) Walnut crossed with single produces 1 walnut, 1 rose, 1 pea and 1 single offspring. B) Rose crossed with pea produces 20 walnut offspring. C) Pea crossed with single produces 1 single offspring.arrow_forwardOne particularly useful feature of the Hardy-Weinberg equation is that it allows us to estimate the frequency of heterozygotes for recessive genetic diseases, assuming that Hardy-Weinberg equilibrium exists. As an example, let’s consider cystic fibrosis, which is a human genetic disease involving a gene that encodes a chloride transporter. Persons with this disorder have an irregularity in salt and water balance. One of the symptoms is thick mucus in the lungs that can contribute to repeated lung infections. In populations of Northern European descent, the frequency of affected individuals is approximately 1 in 2500. Because this is a recessive disorder, affected individuals are homozygotes. Assuming that the population is in Hardy-Weinberg equilibrium, what is the frequency of individuals who are heterozygous carriers?arrow_forward
- Individuals who find the taste of cilantro to be pleasent have a domiant allele for this taste sensation. Individuals who do not like this flavor are recessive. for this particular taste sensation. A parent who does not like Cilantro has a child with someone who is homozygous dominant for liking the flavor of Cilantro. What are the chances that teh child will not like the Cilantro? a) 25% b) 50% c) 0% d)100%arrow_forwardLet's continue with these two genes that control the color and texture of tomatoes. Allele "R" generates a red coloration, and is dominant. Allele "r" generates a green coloration and is recessive. Allele "S" generates a smooth texture, and is dominant. Allele "s" generates a rough texture and is recessive. You now decide to cross your dihybrid RrSs but this one with a tomato with Rrss. RrSs x Rrss What is the probability of getting Red tomatoes with Rough texture in this new cross? Assume complete dominance and 100% penetrance and expressivity. 9/16 3/8 1/4 1/16 3/16 1/8 x 1/2arrow_forwardSickle cell anemia is caused by a recessive allele at a single gene. As we discussed in class, being a homozygote for the sickle cell allele is almost always lethal, but heterozygotes tend to be resistant against malaria although they have a mild form of anemia. Because of this heterozygote advantage, the allele for sickle cell anemia has a frequency of more than 10% in some human populations. How would present allele frequencies of the sickle cell allele change, if there was no heterozygote advantage or disadvantage (that is, that heterozygotes would be identical to ‘normal’ homozygotes – no malaria resistance, no anemia)? How would the change in sickle cell allele frequencies compare to scenario a (extirpation of malaria)arrow_forward
- Consider the following statement: ‘female, w+w flies have red eyes’. In this example: Group of answer choices 1) w+w is the genotype, and red eyes is the phenotype 2) female is the genotype, and red eyes is the phenotype 3) not enough information provided to determine genotype or phenotype 4) red eyes is the genotype, and w+w is the phenotypearrow_forwardIn griffins, coat colour is determined by a single gene with a completely dominant black (B) allele and a recessive white allele (b). Beak shape is determined by a single gene with a completely dominant sharp beak allele (R) and a recessive round beak allele (r). The colour and beak genes are linked by 25 cM(= centimorgans = map units). If a female heterozygous at both loci has the dominant alleles linked in cis, she will produce gametes that have what genotypes in what ratios? Explain your answer.arrow_forwardIn mice, the presence of a dominant A allele results in the agouti pattern of fur color, whereas the aa homozygous recessive results in a solid color pattern. The presence of another dominant B allele results in black fur color, whereas the homozygous recessive bb results in brown fur color. The presence of a third dominant C allele is required for any color to be observed (brown or black), whereas the homozygous recessive cc results in lack of any color whatsoever (albino). What is the phenotype of a mouse with the following genotype? Aa bb cc albino Agouti color pattern and brown Solid color pattern and brown Agouti color pattern and black Solid color pattern and blackarrow_forward
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