Table 2. Calculations ~60°C trial ~50°C trial ~40°C trial ~30°C trial ~20°C trial Vol. of HCI used (mL) 19.87 12.93 12.37 9.03 6.30 Moles of HCI 9.94 6.47 6.19 4.52 3.15 used (mol) Moles of borate present (mol) [Borate] (M) Ksp In(Ksp) 1/T(K-1)

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the data collected in Table 1 fill in the blanks of Table 2

Table 1. Data Collection
~60°C trial
~50°C trial
~40°C trial
~30°C trial
~20°C trial
Actual temp (°C)
58.0
49.0
40.0
31.0
24.0
Vol. borate
solution (mL)
4.97
4.93
5.00
4.97
5.00
Initial buret
reading (mL)
0.00
0.00
0.00
0.00
0.00
Final buret
reading (mL)
19.87
12.93
12.37
9.03
6.30
Transcribed Image Text:Table 1. Data Collection ~60°C trial ~50°C trial ~40°C trial ~30°C trial ~20°C trial Actual temp (°C) 58.0 49.0 40.0 31.0 24.0 Vol. borate solution (mL) 4.97 4.93 5.00 4.97 5.00 Initial buret reading (mL) 0.00 0.00 0.00 0.00 0.00 Final buret reading (mL) 19.87 12.93 12.37 9.03 6.30
Table 2. Calculations
~60°C trial
~50°C trial
~40°C trial
~30°C trial
~20°C trial
Vol. of HCI used
(mL)
19.87
12.93
12.37
9.03
6.30
Moles of HCI
used (mol)
9.94
6.47
6.19
4.52
3.15
Moles of borate
present (mol)
[Borate] (M)
Ksp
In(Ksp)
1/T (K-1)
Transcribed Image Text:Table 2. Calculations ~60°C trial ~50°C trial ~40°C trial ~30°C trial ~20°C trial Vol. of HCI used (mL) 19.87 12.93 12.37 9.03 6.30 Moles of HCI used (mol) 9.94 6.47 6.19 4.52 3.15 Moles of borate present (mol) [Borate] (M) Ksp In(Ksp) 1/T (K-1)
Expert Solution
Step 1

In the given experiment the titration of borate with hydrochloric acid is being carried out at different temperatures. From the give data we are required to calculate the number of moles of borate titrated, concentration of borate at different temperature solubility product and the inverse of temperature. 

 

Note: The number of moles of HCl solution given are taken as millimoles instead of moles as it seems inappropriate to have 9.94 moles of HCl in just 19 mL of solution. 

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