Table 1: Line Data for the Network Line (Bus to Bus) R (Per unit) X (Per Unit) Y/2 (Per Unit) 1-2 0.021 0.08 0.03 1-3 0.015 0.05 0.06 2-4 0.009 0.05 0.04 3-4 0.024 0.09 0.06
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Find Y bus matrix from line data.kindly do it quickly please
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- 5.10 The zero sequence current of a generator for line to ground fault is /2.4 p.u. Then the current through the neutral during the fault is (a) j2.4 p.u. (c) j7.2 p.u. (b) j0.8 p.u. (d) j0.24 p.u.The per-unit quantity is always dimensionless. (a) True (b) FalseDraw the single line diagram and determine the Y bus matrix for the given data. All admittances are given in pu. Bus Line Admittance in PU From To 1 2 -j1.0 3 -j2.5 4 -j5 3 4 -j5 3. -j1.25
- The per unit bus impedance matrix for the power system network of Figure Q1 is given by; r0.240 0.140 0.200 0.2001 Zbus = i0.140 0.2275 0.175 0.175 0.200 0.175 0.310 0.310 Lo.200 0.175 0.310 0.500 j0.20 j0.15 j0.20 j0.20 j0.50 j0.20 j0.30 3 j0.19 Figure Q1 Evaluate the fault current, bus voltages and line currents during fault, when fault occurs at bus 2 with Z: = j0.0225.For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. 0.25 By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is -0.762-j0.826 -0.762+j0.826 0.762+j0.826 0.762-j0.826 By using Gauss-Siedal method, the voltage of the bus 1 after two iteration is 1+j0 0+j1 -0.3-j0.6 0.3-j0.61. FIGURE 52 shows the one-line diagram of a simple three-bus power system with generation at bus I. The voltage at bus l is V1 = 1.0L0° per unit. The scheduled loads on buses 2 and 3 are marked on the diagram. Line impedances are marked in per unit on a 100 MVA base. For the purpose of hand calculations, line resistances and line charging susceptances are neglected a) Using Gauss-Seidel method and initial estimates of Va 0)-1.0+)0 and V o)- ( 1.0 +j0, determine V2 and V3. Perform two iterations (b) If after several iterations the bus voltages converge to V20.90-j0.10 pu 0.95-70.05 pu determine the line flows and line losses and the slack bus real and reactive power. 2 400 MW 320 Mvar Slack 0.0125 0.05 300 MW 270 Mvar FIGURE 52
- For the system shown in figure obtain the positive sequence, negative sequence and zero sequence bus impedance matrices. Data are given in table. T₁ 1 2 G₁ to Coto 4+ Item G₁ G₂ Ti T2 Line 1-2 X¹ X² xº 0.10 0.10 0.05 0.10 0.10 0.05 0.25 0.25 0.25 0.25 0.25 0.25 0.30 0.30 0.50 3 T₂ 4 340 G₂For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- 0.25 Ybus j -0.2 -0.2 -0.05 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ₂=0.6+j0.25 p.u., P3+jQ3=0.8+j0.5 p.u. By using Gauss-Siedal method, the voltage of the bus 3 after two iteration is -0.076+j0.5566 O -0.076-j0.5566 O 0.076+j0.5566 0.076-j0.55665.10 The zero sequence current of a generator for line to ground fault is j2.4 p.u. Then the current through the neutral during the fault is (a) j2.4 p.u. (b) j0.8 p.u. (d) j0.24 p.u. (c) i7.2 p.u.
- For a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- 0.25 Ybusj -0.2 -0.2 0.225 -0.05 -0.025 -0.05 -0.025 p.u. 0.075 V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. -0.762-j0.826 -0.762+10.826 O 0.762+j0.826 0.762-j0.826 By using Gauss-Siedal method, the voltage of the bus 2 after two iteration ismachine The per unit impedance of a synchronous is 0.242. If the base voltage is increased by 1.1 times, the per unit value will be a) 0.266 c) 0.220 b) 0.242 d) 0.200use Kirchhoff Law