TA-5. For each of these single displacement reactions: (1) Write a balanced molecular equation, including all physical states. Use the solubility rules provided on the Course Resources page. (2) Write a balanced total ionic equation, including all physical states and charges for individual ions. (3) Write a balanced net ionic equation, including all physical states and charges for individual ions. (4) State what is oxidized and briefly explain how you can tell. (5) State what is reduced and briefly explain how you can tell. а. barium and manganese(II) acetate

Complete and balance the following acid-base and acid-carbonate reactions. (Use the lowest possible whole number coefficients.) (a)    HCl + Ba(OH)2 → (b)    HCl + Al2(CO3)3 → (c)    H3PO4 + LiHCO3 → (d)    Al(OH)3 + H2SO4 →

For each reaction in the table below, write the chemical formulae of any reactants that will be oxidized in the second column of the table. Write the chemical formulae of any reactants that will be reduced in the third column. reactants reactants reaction oxidized reduced 2Cu(s) + I, (s) → 2CuI (s) 0, (8) + Cr(s) → Cro, (s) 8Ca (s) + S, (s) → 8CAS (s)

Consider a double replacement reaction between Zinc (ll) chloride and sodium hydroxide: ZnCl2+NaOH ==> Complete the chemical equation by: 1. Rewriting it to include electrically-neutral ionic product formulas for each formula. To clarify instead of just writing the product formulas rewrite the entire equation. Concerning the "electrically neutral" part, you are reminded that if for example, Na + Cl2 ==> were your reactants, you would not predict NaCl2 as a chemical product because that is not an electrically neutral compound formula. The Na would have a +1 charge and, the Cl would have a -1 charge, 2 (-1) charges would give an overall -2 charge which would not produce an overall 0 charge. 2. Balance it. 3. Add subscripts (aq, I, s, or g) to show how the reactants combine and which product will precipitate to be collected as a solid. 4. Provide subscripts for both reactants and both products.