T8 When 1.836 L of 6.000 M hydrochloric acid react with excess iron how many liters of hydrogen gas form at 25.0°C and 1.00 atm? This and the next 2 questions use the reaction: 2 Fe (s) + 6 HCI (aq) 2 FeCl3 (aq) + 3 H2 (g) -> Select one: a. 0.5637 mol b. 0.03132 mol C. none of these d. 0.09395 mol e. 16.4 L f. 5.508 mol g. 0.1879 mol h. 135 L

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How many moles of hydrochloric acid are needed to produce 26.3 L of chlorine gas according to the following reaction at 0 °C and 1 atm?hydrochloric acid (aq) + oxygen(g)water (l) + chlorine(g) moles hydrochloric acid

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7.78 18) How many grams of zinc metal are required to produce 2.00 liters of hydrogen gas at STP 24.5 Zn(s) + 2 HCl(aq) A) 0. 171 g according to the chemical equation shown below? → ZnCl2(aq) + H2(g) C) 5.83 g B) 131 g D) 11.7 g any to raise the temperature of 53.8 g benzene by

In the video, a 5.0 L flask at 20°C was shown, containing 1.25 mol of He and 0.50 mol of H₂, at a total pressure of 8.4 atm. Which of the following outcomes would you expect of an additional 0.50 mol of H₂ were added to the flask? Select all that apply. the mole fraction of H₂ would double the partial pressure of He would remain the same the mole fraction of He would remain the same the total gas pressure would increase by 50% the total mass of gas would increase by about 1.0 g

You are given the balanced equation: C3H8 + 5 02 3 CO2 + 4 H20 If 0.3618 moles of CaHg are allowed to react with 1.818 moles of O2, and this is the only reaction which occurs, what is the theoretical yield of water (in moles) that could be produced? O 1.456 moles O 1.447 moles O 2.180 moles . O 1.454 moles

How many liters of CO2 gas are formed at STP when 15.0 grams of HCl reacts completely with Na2CO3? 1Na2CO3(s)+2HCl(g)--> 1H2O(l) + 2NaCl(aq)+ 1CO2 (g)

Carbon dioxide can be made in the lab by the reaction of hydrochloric acid with calcium carbonate. CaCO3 (s) + 2 HCl (aq) --> CaCl2 (aq) + H2O (l) + CO2 (g) How many milliliters of CO2 at 20.0C and 745 torr can be prepared from a mixture of 12.3 g CaCO3 and 185 mL of 0.250 M HCl?