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Q: If w = 40 N in the equilibrium situation shown, find T, and T2. 60 T T2 70°
A: Given: The weight is 40 N.
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A: Required : The correct option.
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A: Answer:Option d
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A: Given: mass m=0.045 kg k=490 N/m ∆x=0.13 2.2 J is lost due to friction, v=6.4 m To find: h=?
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A: in this question we use free body diagram to solve question.
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- As shown below, the coefficient of kinetic friction between the surface and the larger block is 0.20, and the coefficient of kinetic friction between the surface and the smaller block is 0.30. lf F=10Nand M=1.0kg , what is the tension in the connecting string?As shown below, if M=6.0kg, what is the tension in the connecting string? The pulley and all surfaces are frictionless.While sliding a couch across a floor, Andrea and Jennifer exert forces FA and FJ on the couch. Andrea’s force is due north with a magnitude of 130.0 N and Jennifer’s force is 32 east of north with a magnitude of 180.0 N. (a) Find the net force in component form. (b) Find the magnitude and direction of the net force. (c) If Andrea and Jennifer’s housemates, David and Stephanie, disagree with the move and want to prevent its relocation, with what combined forceFDS should they push so that the couch does not move?
- Propose a force standard different from the example of a stretched spring discussed in the text. Your standard must be capable of producing the sane force repeatedly.A skydiver is at an altitude of 1520 m. After 10.0 seconds of free fall, he opens his parachute and finds that the air resistance, FD , is given by the formula FD=bv , where bis a constant and vis the velocity. If b=0.750 , and the mass of the skydiver is 82.0 kg, first set up differential equations for the velocity and the position, and then find: (a) the speed of the skydiver when the parachute opens, (b) the distance fallen before the parachute opens, (c) the terminal velocity after the parachute opens (find the limiting velocity), and (d) the time the skydiver is in the air after the parachute opens.In the following figure m = 20.0 kg and a622 The coetticient of kinetic friction betwoen the biock and the incline is a -0.40 (Eigure 1) Part A What must be the mass my of the hanging block ifit ia to descend 14.5 m in the tinst 3.00 s after the system is neleaned from rest? Express your anewer with the appropriate units. Figure t of 1 my Value Units Submit Bequest Aner Provide Feedback Next>
- A light rope is attached to a block with mass 4.00 kg that restson a frictionless, horizontal surface. The horizontal rope passes overa frictionless, massless pulley, and a block with mass m is suspendedfrom the other end. When the blocks are released, the tension in therope is 15.0 N. Draw two free-body diagrams: one for each block.e.co CU ct sona- n ect Pool artment... W 24,919 8. A mass m₁ = 9.00 kg is connected by a light string that passes over a pulley of mass M = 14.0 kg to a mass m₂ = 12.5 kg sliding on a horizontal frictionless surface (see figure). There is no slippage between the string and the pulley. What is the magnitude of the tension that is acting on mass m₂? (The moment of inertia of the pulley is ½/Mr².) N # 3 20 $ 4 R 999 F4 % 5 FS ^ 6 tv © MacBook Air Y & 7 m₂ F7 * 8 Dall 1 ( 9 M m₁ A 02 DD ) 0 P ISULI H by mi 04 M vauies or roe pufferA rope passes over a frictionless pulley at B as shown. (a) If the mass of the body C is 40 kg, what must be the mass of body A to hold the assembly in the position shown. (b) What is the tension in DE? В 30° E D A
- A rope passes over a frictionless pulley at B as shown. (a) If the mass of the body A is 40 kg, what must be the mass of body C to hold the assembly in the position shown. (b) What is the tension in DE? B 30° D AI created a free body diagram but need help explaining how the slope of the ramp can be used to determine the coefficient of friction. Im trying to use math to exaplain using μ = tan(θ) and my rise is 15cm and my run is 55cm. My teacher taught us SOH CAH TOA but im not sure how I would expalin using math. Please help me out!esmat.h... Figure Lobby | Top Hat A uniform board of length L and mass M lies near a boundary that separates two regions. In region 1, the coefficient of kinetic friction between the board and the surface is μ, and in region 2, the coefficient is 2. The positive direction is shown in the figure. (Figure 1) Before: region 1 After: 141 Aktiv Chemistry FI 1₂ D2L Homepage - Vande... M Gmail 12 1 of 1 > region 2 4 Part A W = Submit Handshake VYES - Vanderbilt - S... Find the net work W done by friction in pulling the board directly from region 1 to region 2. Assume that the board me constant velocity. Express the net work in terms of M, g, L, ₁, and μ2. ►View Available Hint(s) IVE ΑΣΦ Part B Complete previous part(s) Provide Feedback Course Home P Pearson ? Review | Co Copyright ©2022 Pearson Education Inc. All rights reserved | Terms of Use | Privacy Policy Pormin ▬▬▬▬