T A gas of unknown identity diffuses at a rate of 89.3 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate of 104 mL/s. Calculate the molecular mass of the unknown gas.

https://youtu.be/TM3YiYajGf4?si=v8GatfHVrWh6zo02   In an observation table record the relative volumes of gas in the three sealed bags. Is there evidence that the amount of product formed is related to the amount of reactants used? Is there evidence that some of the baking soda has not completely reacted in one or more of the bags? Open each bag and add 15mL of vinegar to each. Is there evidence that a shortage of vinegar was limiting the production of carbon dioxide gas in some bags? Add 15mL of baking soda to each bag. Is there evidence that a lack of baking soda was limiting the production of carbon dioxide in some bags?

The rate of effusion of a particular gas was measured and found to be 24.0mL/min. Under the same conditions the rate of effusion of pure methane( CH4) has is 47.8mL/min. What is the molar mass of the unknown gas

To determine the molecular weight of an unknown chlorate. a sample of the chlorate was decomposed by heating and the oxygen gas produced was collected over water.563mL of oxygen were collected. The gas collected and the water were both at a temperature of 24°C. The total pressure of the room was 0.996 atm. If the vapor pressure of water at 24°C is 25.8 torr, howmany moles of gas were collected?R = 0.08206* L*atm/ mol*K

A sample of O2 gas is observed to effuse through a porous barrier in 7.64 minutes. Under the same conditions, the same number of moles of an unknown gas requires 12.7 minutes to effuse through the same barrier. The molar mass of the unknown gas is g/mol.

A gas of unknown molecular mass was allowed to effuse through a small opening under constant pressure conditions. It required 72 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 27 s for 1.0 L of 02 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; that is, rate and time are inversely proportional.) 367.1175859 X g/mol

MI < CO C. Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 5.75 mL of O2 had passed through the membrane, but only 3.86 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas? unknown molar mass: g/mol MacBook Pro The %23 %$4 delet 4. 5. 3. R. P. H. K. B. MOSISO command uondo

A sample of SO2 gas is observed to effuse through a porous barrier in 5.45 minutes. Under the same conditions, the same number of moles of an unknown gas requires 4.27 minutes to effuse through the same barrier. The molar mass of the unknown gas is g/mol.

A sample of O3 gas is observed to effuse through a pourous barrier in 1.06 minutes. Under the same conditions, the same number of moles of an unknown gas requires 0.736 minutes to effuse through the same barrier. The molar mass of the unknown gas is g/mol.

Match the characteristic of gases described below to the postulates of the kinetic molecular theory that best explain that characteristic. (Note: You may need to list more than one postulate.) The pressure of a gas in a fixed volume increases when its temperature increases. Select one or more: The average kinetic energies of gas particles increase with an increase in temperature. Gas particles are widely spaced. A gas consists of many small particles in rapid, random motion. The total volume of the molecules themselves is very small compared to the volume of the container. There are virtually no attractive forces between gas particles.