Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Formulation of the solution and Interpretation of the solution of this. Essay type. Thanks.
E Untitled2.mlx *
LIVE EDITOR
INSERT
VIEW
圖
a Find Files
企业
Aa Normal
A Run Section
2 Control -
E Compare
Go To -
BIUM
E Run and Advance
Section
Break P Run to End
New
Open
Save
Тext
* Refactor E E F
Run
Step
Stop
A Print
Q Find -
FILE
NAVIGATE
TEXT
CODE
SECTION
RUN
X =
syms t
-241
60 sin( 16) e
2
3
x=60*sin(16*t)*exp(-((24*t)/5))% Displacement
V =
4
V=diff(x)% Velocity
-241
960 cos(161) e5 - 288 sin(161) e
6
a-diff(x,2) % Acceleration
a =
8
241
-24
-9216 cos(16 t) e
69888 sin(16 1) e
9
clear all
10
t=0;
11
display('displacemt at t-0')
displacemt at t-e
12
x-60*sin(16*t)*exp(-((24*t)/5))
13
display('Velocity at t=0')
v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5))
14
Velocity at t=0
15
v = 960
16
display('Acceleration at t=0')
a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-((24*t)/5)))/5 % Displacement
clear all
17
Acceleration at t=0
18
a - -9216
-
19
20
t=0.3
t = 0.3000
display('displacemt at t-e')
x-60*sin(16*t)*exp(-((24*t)/5))
þisplay('Velocity at t=0.3')
v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5))
21
displacemt at t-e
22
x = -14.1611
23
Velocity at t=0.3
24
v = 87.8752
25
26
display('Acceleration at t-0.3')
Acceleration at t-0.3
a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-(( 24*t)/5)))/5 % Displacement
a = 3.1079e+03
27
script
Ln 23
Col 1
1:09 AM
P Type here to search
a 4)
12/16/2021
44°F Haze
ヘ口
expand button
Transcribed Image Text:E Untitled2.mlx * LIVE EDITOR INSERT VIEW 圖 a Find Files 企业 Aa Normal A Run Section 2 Control - E Compare Go To - BIUM E Run and Advance Section Break P Run to End New Open Save Тext * Refactor E E F Run Step Stop A Print Q Find - FILE NAVIGATE TEXT CODE SECTION RUN X = syms t -241 60 sin( 16) e 2 3 x=60*sin(16*t)*exp(-((24*t)/5))% Displacement V = 4 V=diff(x)% Velocity -241 960 cos(161) e5 - 288 sin(161) e 6 a-diff(x,2) % Acceleration a = 8 241 -24 -9216 cos(16 t) e 69888 sin(16 1) e 9 clear all 10 t=0; 11 display('displacemt at t-0') displacemt at t-e 12 x-60*sin(16*t)*exp(-((24*t)/5)) 13 display('Velocity at t=0') v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5)) 14 Velocity at t=0 15 v = 960 16 display('Acceleration at t=0') a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-((24*t)/5)))/5 % Displacement clear all 17 Acceleration at t=0 18 a - -9216 - 19 20 t=0.3 t = 0.3000 display('displacemt at t-e') x-60*sin(16*t)*exp(-((24*t)/5)) þisplay('Velocity at t=0.3') v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5)) 21 displacemt at t-e 22 x = -14.1611 23 Velocity at t=0.3 24 v = 87.8752 25 26 display('Acceleration at t-0.3') Acceleration at t-0.3 a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-(( 24*t)/5)))/5 % Displacement a = 3.1079e+03 27 script Ln 23 Col 1 1:09 AM P Type here to search a 4) 12/16/2021 44°F Haze ヘ口
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