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Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Question
Describe each line of the program/script.

Transcribed Image Text:E Untitled2.mlx *
LIVE EDITOR
INSERT
VIEW
圖
a Find Files
企业
Aa Normal
A Run Section
2 Control -
E Compare
Go To -
BIUM
E Run and Advance
Section
Break P Run to End
New
Open
Save
Тext
* Refactor E E F
Run
Step
Stop
A Print
Q Find -
FILE
NAVIGATE
TEXT
CODE
SECTION
RUN
X =
syms t
-241
60 sin( 16) e
2
3
x=60*sin(16*t)*exp(-((24*t)/5))% Displacement
V =
4
V=diff(x)% Velocity
-241
960 cos(161) e5 - 288 sin(161) e
6
a-diff(x,2) % Acceleration
a =
8
241
-24
-9216 cos(16 t) e
69888 sin(16 1) e
9
clear all
10
t=0;
11
display('displacemt at t-0')
displacemt at t-e
12
x-60*sin(16*t)*exp(-((24*t)/5))
13
display('Velocity at t=0')
v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5))
14
Velocity at t=0
15
v = 960
16
display('Acceleration at t=0')
a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-((24*t)/5)))/5 % Displacement
clear all
17
Acceleration at t=0
18
a - -9216
-
19
20
t=0.3
t = 0.3000
display('displacemt at t-e')
x-60*sin(16*t)*exp(-((24*t)/5))
þisplay('Velocity at t=0.3')
v=960*cos (16*t)*exp(-((24*t)/5)) - 288*sin(16*t)*exp(-((24*t)/5))
21
displacemt at t-e
22
x = -14.1611
23
Velocity at t=0.3
24
v = 87.8752
25
26
display('Acceleration at t-0.3')
Acceleration at t-0.3
a=- 9216*cos(16*t)*exp(-((24*t)/5)) - (69888*sin(16*t)*exp(-(( 24*t)/5)))/5 % Displacement
a = 3.1079e+03
27
script
Ln 23
Col 1
1:09 AM
P Type here to search
a 4)
12/16/2021
44°F Haze
ヘ口
Expert Solution
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