Suppose we wish to evaluate limx→0x10sin(2x)+8.Since we know that −1≤sin(θ)≤1 for θ∈R, we must haveCorrect ≤sin(2x)≤ Correct for x≠0. Part 2 of 4 From this, we must have ≤x10sin(2x)≤ for x≠0. ≤x10sin(2x)+8≤ for x≠0.
Suppose we wish to evaluate limx→0x10sin(2x)+8.Since we know that −1≤sin(θ)≤1 for θ∈R, we must haveCorrect ≤sin(2x)≤ Correct for x≠0. Part 2 of 4 From this, we must have ≤x10sin(2x)≤ for x≠0. ≤x10sin(2x)+8≤ for x≠0.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Suppose we wish to evaluate limx→0x10sin(2x)+8.
Since we know that −1≤sin(θ)≤1 for θ∈R, we must have
Correct ≤sin(2x)≤ Correct for x≠0.
Since we know that −1≤sin(θ)≤1 for θ∈R, we must have
Correct ≤sin(2x)≤ Correct for x≠0.
Part 2 of 4
From this, we must have
≤x10sin(2x)≤ for x≠0.
≤x10sin(2x)+8≤ for x≠0.
≤x10sin(2x)≤ for x≠0.
≤x10sin(2x)+8≤ for x≠0.
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