Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle = 35.0", a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v,, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is ty, the y-component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y 0 t=0 Xo = 0 Yo=0 Vo = 0 x =? y =? V₂ =? Vy =? a = 1.25 m/sec² L = 200 m Let's now re-define the time to t= 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. h) What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. y Re-define as t = 0 xo yo Vox Voye |Ymar =? \t=? y = 0 x =?

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter6: Applications Of Newton's Laws
Section: Chapter Questions
Problem 76P: The CERN particle accelerator is circular with a circumference of 7.0 km. (a) What is the...
icon
Related questions
icon
Concept explainers
Topic Video
Question
100%

answer f, g and h

Problem 4:
A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an
angle 0 = 35.0°, a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the
rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure
below.
a) What is x? Answer: 163.8 m.
b) What is y? Answer: 114.7 m.
c)
What is v₂, the x-component of the rocket at the top of the inclined plane?
Answer: 18.3 m/sec.
d) What is vy, the y -component of the rocket at the top of the inclined plane?
e) Answer: 12.8 m/sec.
y
y
t = 0
Xo = 0
Yo=0
0
t
x = ? y =?
Vx =? Vy = ?
a = 1.25 m/sec²
L = 200 m
Vo = 0
Let's now re-define the time to t = 0. At this instant, the acceleration of the rocket shuts off
and now we have the rocket in projectile motion. The final properties of the rocket from the
rocket at the top of the incline now make the initial properties for the projectile motion.
See the figure below.
f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m.
g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec.
h) What
is x, the x-position at which the rocket hits the ground? Answer: 279.1 m.
x
Re-define as t = 0
xo Yo
LIE
Vox Poyr
|Ymax =?
t=?
y = 0 x =?
x
Transcribed Image Text:Problem 4: A rocket starts from rest at the origin. The rocket accelerates up an inclined plane of with an angle 0 = 35.0°, a length L = 200 m, and an acceleration a = 1.25 m/sec². At a time t the rocket reaches the top of the inclined plane at the location (x, y) with a speed v. See the figure below. a) What is x? Answer: 163.8 m. b) What is y? Answer: 114.7 m. c) What is v₂, the x-component of the rocket at the top of the inclined plane? Answer: 18.3 m/sec. d) What is vy, the y -component of the rocket at the top of the inclined plane? e) Answer: 12.8 m/sec. y y t = 0 Xo = 0 Yo=0 0 t x = ? y =? Vx =? Vy = ? a = 1.25 m/sec² L = 200 m Vo = 0 Let's now re-define the time to t = 0. At this instant, the acceleration of the rocket shuts off and now we have the rocket in projectile motion. The final properties of the rocket from the rocket at the top of the incline now make the initial properties for the projectile motion. See the figure below. f) What is ymax, the highest elevation of the rocket above the ground? Answer: 123.1 m. g) What is t, the time at which the rocket hits the ground? Answer: 6.3 sec. h) What is x, the x-position at which the rocket hits the ground? Answer: 279.1 m. x Re-define as t = 0 xo Yo LIE Vox Poyr |Ymax =? t=? y = 0 x =? x
-b+√b²-4ac
2a
x = x₂ + V₁xt + ²axt², V₁₁x = V₁x + axt, (v₁₁x)² = (v₁x)² + 2axx, t ==
у = V₁ + V₁¸yt + ² α¸t², Vf₁y = V₁y+āÿt, (Vƒ‚y)² = (v₁y)² + 2a,ÿ
Transcribed Image Text:-b+√b²-4ac 2a x = x₂ + V₁xt + ²axt², V₁₁x = V₁x + axt, (v₁₁x)² = (v₁x)² + 2axx, t == у = V₁ + V₁¸yt + ² α¸t², Vf₁y = V₁y+āÿt, (Vƒ‚y)² = (v₁y)² + 2a,ÿ
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Displacement, velocity and acceleration
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill