Question
Suppose we are doing ordinary least-squares linear regression with a fictitious dimension. Which of the
following changes can never make the cost function’s value on the training data smaller?
A: Discard the fictitious dimension (i.e., don’t append a 1 to every sample point).
B: Append quadratic features to each sample point.
C: Project the sample points onto a lower-dimensional subspace with PCA (without changing the labels) and
perform regression on the projected points.
D: Center the design matrix (so each feature has mean zero).
SAVE
AI-Generated Solution
info
AI-generated content may present inaccurate or offensive content that does not represent bartleby’s views.
Unlock instant AI solutions
Tap the button
to generate a solution
to generate a solution
Click the button to generate
a solution
a solution
Knowledge Booster
Similar questions
- We've built a logistic regression model in RapidMiner, and would like to use it to make predictions for some new data points. Which operator do we need: Performance Apply Model Cross Validation O Nominal to Numerical.arrow_forward• Implement and test: • Logistic regression (LR) with L1 regularization • LR is differentiable • But L1 norm is not • Use proximal gradient descent • For L1 norm, that’s soft-thresholding • Use tensorflow library • Dataset – the same as in HW2: • Classify two digits from MNIST dataset • See: tensorflow_minimizeF.py • Performs projected gradient descent on a simple function • The function has global minimum at • w1=-0.25, w2=2 • But the feasible set Q is: w1>=0, w2>=0 • For this function, the best solution is w1=0, w2=2 • The code does the following, in a loop: • Gradient step on the function, followed up by proximal step • Here, the proximal step is just “make w nonnegative” by replacing negative values with 0, the closest non-negative value • Feasible set Q is set of all vectors with nonnegative coordinates, i.e., for 2D, w1>=0, w2>=0 • In your actual code, you should use soft-thresholding instead • See: tensorflow_leastSquares.py • Performs gradient descent on a function…arrow_forwardThis is a binary classification problem, y has two values (0 or 1), and X (feature) has three dimensions. • Use a logistic regression model to project X to y (classify X into two categories: 0 or 1). • The initialization is: w1 = 0, w2 = 0, w3 = 0, b = 0, Learning rate is 2. • You must use Gradient Descent for logistic regression in this question. • The regression should stop after one iteration. Calculation process and formulas must be included in your answer! You must answer this question by manual calculation, but not programming.arrow_forward
- Assume the following simple regression model, Y = β0 + β1X + ϵ ϵ ∼ N(0, σ^2 ) Now run the following R-code to generate values of σ^2 = sig2, β1 = beta1 and β0 = beta0. Simulate the parameters using the following codes: Code: # Simulation ## set.seed("12345") beta0 <- rnorm(1, mean = 0, sd = 1) ## The true beta0 beta1 <- runif(n = 1, min = 1, max = 3) ## The true beta1 sig2 <- rchisq(n = 1, df = 25) ## The true value of the error variance sigmaˆ2 ## Multiple simulation will require loops ## nsample <- 10 ## Sample size n.sim <- 100 ## The number of simulations sigX <- 0.2 ## The variances of X # # Simulate the predictor variable ## X <- rnorm(nsample, mean = 0, sd = sqrt(sigX)) Q1 Fix the sample size nsample = 10 . Here, the values of X are fixed. You just need to generate ϵ and Y . Execute 100 simulations (i.e., n.sim = 100). For each simulation, estimate the regression coefficients (β0, β1) and the error variance (σ 2 ). Calculate the mean of…arrow_forwardPlease implement Multinomial Logistic Regression on the following data. Please continue from the given code:arrow_forwardWe want to create an extra feature for the following data with only one feature (x) to use in a multiple linear regression model. What feature should we add? 6.0 V 5.5 50 40 35 30 -1.00 Linear Cubic Quadratic Logarithmic -0.50 -0.25 0:00 0.25 0.50 0.75 1.00arrow_forward
arrow_back_ios
arrow_forward_ios