College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Suppose the object is held 7.50 cm from a convex lens of focal length 10.0 cm, such as a typical magnifying glass might have. What magnification is produced?
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- A student with normal sight is surprised to see a possum scampering up the rear wall in the Lyle theatre. The possum is 30.0 cm long and the wall is 2.3 m away. The student's eyeballs have a diameter of 2.4 cm. How big is the image of the possum on the student's retina? (Units: cm)arrow_forwardThe projection lens in a certain slide projector is a single thin lens. A slide 24.8 mm high is to be projected so that its image fills a screen 1.82 m high. The slide-to-screen distance is 3.04 m. (Enter your answers to at least one decimal place.) (a) Determine the focal length of the projection lens. mm (b) How far from the slide should the lens of the projector be placed to form the image on the screen? mmarrow_forwardPlease Asaparrow_forward
- An object is placed in 5 cm in front of a lens, producing an image that is upright and 3 times larger, m = +3. Determine the position of the image and the focal length of the lens.arrow_forwardThe distance between the eyepiece and the objective lens in a certain compound microscope is 19.0 cm. The focal length of the eyepiece is 2.45 cm and that of the objective is 0.395 cm. What is the overall magnification of the microscope? dditiarrow_forwardA transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.arrow_forward
- The projection lens in a certain slide projector is a single thin lens. A slide 23.0 mm high is to be projected so that its image fills a screen 1.90 m high. The slide-to-screen distance is 3.06 m. (Enter your answers to at least one decimal place.) (a) Determine the focal length of the projection lens. mm(b) How far from the slide should the lens of the projector be placed to form the image on the screen? mmarrow_forwardProblem 11: A pair of binoculars has an angular magnification of -7.5, when acting as a telescope (in most binoculars mirrors are used to make the image upright; we will not consider the effect of these mirrors here). If the binoculars have objective lenses with a focal length of 15 cm, what is the focal length, fe, of the eyepiece in centimeters?arrow_forwardAn object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright invertedarrow_forward
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