A compound microscope is made with an objective lens (fo = 0.90 cm) and an eyepiece (fo = 1.1 cm). The lenses are separated by a distance of 10 cm. If an object is 1.0 cm in front of the objective lens, where will the final image of the eyepiece be located?

A lens forms an image of an object. The object is 16 cm from the lens. The image is 12 cm from the lens on the same side as the object. (a) What is the focal length of the lens? (b) If the object is 8.5 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a ray diagram.

You are using a microscope with a 10× eyepiece. What focal length of the objective lens will give a total magnification of 200×? Assume a length L = 160 mm.

Two lenses are mounted d = 39 cm apart on an optical bench. The focal length of the first lens is f1 = 9.8 cm and that of the second lens is f2 = 3.1 cm. An object of height ho = 4.9 cm is placed at a distance of do = 24 cm in front of the first lens. Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image?  D =?

A compound lens system consists of two converging lenses, one at x=−20.0cm with focal length f1=+10.0cm, and the other at x=+20.0cm with focal length f2=+8.00cm. (Figure 1) An object 1.00cm tall is placed at x=−50.0cm. (A) What is the location of the final image produced by the compound lens system? Give the x coordinate of the image. Express your answer in centimeters, to three significant figures or as a fraction.

You want to purchase a microscope for doing surgeries, which requires that there is at least 10cm distance between the objective lens and the patient. The objective forms a highly magnified real image of the object at a distance L. You want the image to look 50 times larger. What should be focal lengths of the objective and the eye piece assuming L=200mm

The distance between the eyepiece and the objective lens in a certain compound microscope is 19.0 cm. The focal length of the eyepiece is 2.45 cm and that of the objective is 0.395 cm. What is the overall magnification of the microscope? dditi

A transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.

Consider a converging lens with focal length 7.05 cm. The distance between an object and a real image of the object created by the lens is 50.5 cm. Find the distance between the object and the lens if the lens is closer to the object than it is to the image. Answer in cm.

An object is placed to the left of a lens, and a real image is formed to the right of the lens. The image is inverted relative to the object and is one-half the size of the object. The distance between the object and the image is 73.0 cm. (a) How far from the lens is the object? (b) What is the focal length of the lens? (a) do = (b) f=