-ASuppose that in a random selection of 100 colored candies, 20% of them are blue. The candy company claims that the percentage of blue candies is equal to 28%. Use a 0.05 significance level totest that claim.VCF2OA. Ho: p*0.28H₁: p=0.28w an example Get more help.HdXB. Ho: p=0.28H₁: p>0.28DC. Ho: p=0.28H₁: p 0.28OD. Ho: p=0.28H₁: p<0.28Identify the test statistic for this hypothesis test.The test statistic for this hypothesis test is -1.78(Round to two decimal places as needed.)Identify the P-value for this hypothesis test.The P-value for this hypothesis test is.(Round to three decimal places as needed.)Monroe's Temp.....docxRemoved#3F3E8.0DC$4AaF4RFVSAMPLE Persuas....pdf%5FSTG1^6BF6MacBook AirYI' [0] √₁ Vi 11,HD 5373255 (1) (1).docx&7NF7UJ*8DIIFBIM(9K(0,0) More5373255 (1).docxO)OLcommandF10P>Clear all-...IF11{option[+=?111Check answer1Show AllF12X}]XdeleteI

Given,The sample size (n) = 100The 20% of them are blue so p̂ = 0.20The significance level (α) =…

Answered: Suppose that in a random selection of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
45. Which one of the following is not a common level of significance set in statistical analysis? a. 90% b. 50% c. 95% d. 99%
In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…
A sample of n = 10 has s = 3. What are the correct values for S.S. and s2? SS=44;sampleS.D.=3 SS = 81; sample variance = 9 SS = 30; sample variance = 4 SS=27;sampleS.D.=2
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2. Jim Miller works in the personnel department for a car company. He is told by his supervisor to investigate the difference in the average number of sick days between blue collar workers and whitecollar workers. So he obtained a random sample of 9 blue collar workers and a random sample of 9 white collar workers. He records the results below.At 10% level of significance, is there sufficient evidence to indicate a difference in mean sick days between blue collar workers and white collar workers.
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14.
Q5. With 0.05 significance level, H1: p > 0.5, and the value of test statistic is z = 1.93. Then theP-value is equal to 0.9732.a. Trueb. False
A. For which data set is the sample correlation coefficient r closest to −1? B. For which data set is the sample correlation coefficient r closest to 0? C. For which data set is the sample correlation coefficient r equal to 1?
Question 2 > The average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty- year-olds have a different number of cavities? The data show the results of a survey of 14 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 8, 7, 7, 9, 7, 10, 9, 8, 10, 6, 9, 6, 8 What can be concluded at the a = 0.05 level of significance? %3D a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: |? Select an answer H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that . The data suggest the populaton mean is significantly different from 7 at a = 0.05, so there is sufficient evidence to conclude that the…
M. 山 Find the standardized test statistic, z, to test the claim that p, < P2. The sample statistics listed below are from independent samples. n = 550, x, = 121, and n, = 690, x, = 195 %3D O A. 1.116 O B. -2.132 OC. -2.513 O D. -0.985 P Type here to search 59 F5 F9 F11 %23 3. 5. 6. 8. A G H. B. N Alt

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