Suppose that equal volumes of 0.114 M sodium chloride (NaC) and 0.0888 M silver nitrate (AgNO) are combined. Given the K, for silver chloride is 1.77 x 10", will a precipitate form under these conditions? (A) Cannot be determined without being given the volume of each solution that were combined (B) Yes, because Q 0.0101 No, because Q0.0101 (C) (D) Yes, because Q=0.00253 There is no possible cation/anion pairing that could result in the formation of a precipitate (E)

please provide detailed solution and give the explanation of the concept....     A student ran the following reaction in the laboratory at 656 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 8.62×10-2 moles of NH3(g) into a 1.00 liter container, she found the equilibrium concentration of H2(g) to be 0.118 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = ?

Suppose a 500. mL flask is filled with 0.20 mol of Cl, and 1.5 mol of HCl. The following reaction becomes possible: H,(2) + Cl, (g) – 2HCI(3) The equilibrium constant K for this reaction is 0.754 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places. |M ?

When 12.0 mL of a 2.43×10* M magnesium nitrate solution is combined with 15.0 mL of a 5.89×104 M potassium hydroxide solution does a precipitate form? (yes or no) For these conditions the Reaction Quotient, Q, is equal to

Sulfur dloxlde and oxygen react to form sulfur trioxide during one of the key steps In sulfuric acld synthesis. An industrial chemist studying this reaction fills a 25.0 L tank with 2.0 mol of sulfur dioxide gas and 3.3 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 0.60 mol. Calculate the concentration equlibrlum constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant diglts. K = | Check Explanation Privacy Accessibili 2021 McGraw-Hill Education. All Rights Reserved Terms of Use M9 hp Ce esc

Write the K, expression for the sparingly soluble compound copper(II) hydroxide, Cu(OH),. If either the numerator or denominator is 1, please enter 1.