Suppose that a structural component subjected to environmental corrosion has the potential to fail by a two-step process: First, a crack may initiate with a nominal depth of 5 mils; subsequently, the crack may grow to a sufficient depth that the component fractures. If the initiation time distribution is Lognormal(u = 6.91,0 = 0.06), the crack growth rate has a Weibull(a = 0.4 mils/hr, ß = 1.9) distribution, and failure occurs when the crack depth reaches twenty mils, find the component failure probability after 1100 hours of operation.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
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Suppose that a structural component subjected to environmental corrosion has the potential to fail by a two-step
process: First, a crack may initiate with a nominal depth of 5 mils; subsequently, the crack may grow to a sufficient
depth that the component fractures. If the initiation time distribution is Lognormal(u = 6.91, o = 0.06), the crack
growth rate has a Weibull(a = 0.4 mils/hr, ß = 1.9) distribution, and failure occurs when the crack depth
reaches twenty mils, find the component failure probability after 1100 hours of operation.
Transcribed Image Text:Suppose that a structural component subjected to environmental corrosion has the potential to fail by a two-step process: First, a crack may initiate with a nominal depth of 5 mils; subsequently, the crack may grow to a sufficient depth that the component fractures. If the initiation time distribution is Lognormal(u = 6.91, o = 0.06), the crack growth rate has a Weibull(a = 0.4 mils/hr, ß = 1.9) distribution, and failure occurs when the crack depth reaches twenty mils, find the component failure probability after 1100 hours of operation.
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