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P(A)=0.64,P(B)=0.45,P(B∪A)=0.92
Find the following probabilities.
P(A∩B) =
P(B|A¯) =
P(A¯|B) =
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- For a recent evening at a small, old-fashioned movie theater, 30% of the moviegoers were female and 70% were male. There were two movies playing that evening. One was a romantic comedy, and the other was a World War II film. As might be expected, among the females the romantic comedy was more popular than the war film: 85% of the females attended the romantic comedy. Among the male moviegoers the romantic comedy also was more popular: 65% of the males attended the romantic comedy. No moviegoer attended both movies. Let F denote the event that a randomly chosen moviegoer (at the small theater that evening) was female and F denote the event that a randomly chosen moviegoer was male. Let r denote the event that a randomly chosen moviegoer attended the romantic comedy and R denote the event that a randomly chosen moviegoer attended the war film. Fill in the probabilities to complete the tree diagram below, and then answer the question that follows. Do not round any of your responses.Choose the correct option. (a)−3 (b)3 (c)-5 (d)5Suppose we know that the probabilities P(A) = .5, P(B|A) = .3 and P(A or B) =.3. What is the value for P(A and B)? What is the value for P(B)?
- K Find P(A or B or C) for the given probabilities. P(A)=0.39, P(B) = 0.22, P(C) = 0.11 P(A and B) = 0.12, P(A and C) = 0.02, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =Find P(A or B or C) for the given probabilities. P(A) = 0.34, P(B) = 0.25, P(C) = 0.16 P(A and B) = 0.11, P(A and C) = 0.03, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =first 2 parts please
- For each set of probabilities, determine whether the events A and B are independent or dependent. (If necessary, consult a list of formulas.) Probabilities Independent Dependent = P(A 18) - 1 (a) P(A)=-;P(B) =;P(A\B) = 5 1 1 P(A) =;P (B) = P(A and B) = %3D 4 6. 1 1 P (B|A) = 1 (c) P(4)-극: P(B)-P(Bl4): %3D %3D 1 1 (d) P(A) = : P(B) = P(4 |B) = | %3DPossible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities 0.45, 0.05, 0.45, and 0.05, respectively. (0) Calculate E(X) and then E(5 - X). E(X) - E(5 - X) - 150 (b) Would the repair facility be better off charging a flat fee of $65 or else the amounts (5- X). (Note: It is not generally true that E()- The repair facility Select--- be better off charging a flat fee of s65 because E150 [(5 - x)] -Answers must be in 4 decimals |1. Ben plans to enforce speed limits using radar traps at 4 different locations within the campus. The radar traps at each of the locations L1, L2, L3, and L4 are operated 40%, 30%, 30%, and 20% of the time, and if a person who is speeding on his way to work has probabilities of 0.2, 0.1, 0.5, and 0.2, respectively, of passing through these locations, what is the probability that he will not receive a speeding ticket? 2. Barangay Scout Fernandez has one fire truck and one ambulance available for emergencies. The probability that the fire truck is available when needed is 0.95, and the probability that the ambulance is available when called is 0.90. in the event that there is a fire in the barangay, find the probability that both the ambulance and the fire truck will be available.
