Suppose that a category of world class runners are known to run a marathon (26 miles) in an average of 142 minutes with standard deviation of 14 minutes. Consider 49 of he races. Let’s X̄= the average of the 49 races. Part (d) : Find the median of the average running times _____min

prove that If we multiply the data values by a constant (say, c), value of geometric mean will be affected. how this will affect the geometric mean? Use the equation in image to prove it, and give an example.

solve a b c

The arm span of a team of athletes was measured and listed in the attached image (Problem-Image2.jpg). a) Calculate the mean arm span, ?̄. b) Complete the table and calculate (to two decimal places of accuracy, the standard deviationof the data.). Check the equation in the attached image (Problem-Image3.jpg)

A Biomedical engineer is measuring how much current is needed to stimulate the nerve of a rat to create a muscle function. He is measuring 5 rats and wants to evaluate if less current is needed to stimulate a young animal compared to an old animal. The mean of the current to stimulate young animals is 4.6mA. Meuasrements from trials on Old Rats: 6, 6, 12, 7, 8 (in mA) Can the engineer conclude that old rats need more current?

IQ tests supposedly measure our intelligence. They typically are ‘normed’ so that they have a mean of 100 and a standard deviation of 15. (Higher scores show higher intelligence.) Use the graph and use the z-score and percents from columns b and c in Table A, when relevant. If you scored 132, what is your z-score? (Interpret.) Use table A  X, z(a), (b), and (c) X z (a) (b) (c)          and use the graph! Write down or save your response to use in Part 2 of this quiz. Group of answer choices -2.53 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. 2.13 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. -2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 0.57 percentile rank and 99.43% of people scored smarter than me. 2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 99.43 percentile rank…

Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. The indicated IQ score is (Round to the nearest whole number as needed.) X 0.1753

P-value?